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A vehicle is fitted with an ultrasonic distance sensor as part of parking assistance system which provides echolocation, while the driver is reversing the vehicle. It emits ultrasonic wave (about 40 kHz) which is reflected by the obstacle. When the warning beep starts sounding at a distance of 1.2 m from the obstacle, how much time is taken by ultrasonic wave to travel to the obstacle and come back? Assume the speed of ultrasonic wave in air to be 345 m s⁻¹.

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The total round-trip distance is 2.4 meters. Dividing this distance by the speed of 345 meters per second gives approximately 0.00696 seconds or nearly 6.96 milliseconds, for the wave to return.

Class 9 Science Chapter 10 Sound Waves Characteristics and Applications Solutions

Chapter 10 Sound Waves Characteristics and Applications Question Answer

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  1. The ultrasonic wave travels forward to the obstacle and reflects back, covering a total distance of 2.4 meters. Using the relation time equals total distance divided by speed, dividing 2.4 meters by 345 meters per second yields approximately 0.007 seconds. Therefore, the sensor detects the returning echo in roughly 6.96 milliseconds, triggering the warning beep.

     

    For more NCERT Solutions of Class 9 Science Exploration Chapter 10 Sound Waves Characteristics and Applications Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-10/

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