The total round-trip distance is 2.4 meters. Dividing this distance by the speed of 345 meters per second gives approximately 0.00696 seconds or nearly 6.96 milliseconds, for the wave to return.
Class 9 Science Chapter 10 Sound Waves Characteristics and Applications Solutions
Chapter 10 Sound Waves Characteristics and Applications Question Answer
The ultrasonic wave travels forward to the obstacle and reflects back, covering a total distance of 2.4 meters. Using the relation time equals total distance divided by speed, dividing 2.4 meters by 345 meters per second yields approximately 0.007 seconds. Therefore, the sensor detects the returning echo in roughly 6.96 milliseconds, triggering the warning beep.
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