A Train starting from rest attains a velocity of 90 km/h in 2 min, then the distance travelled by the train for attaining this velocity is:

(A) 1.5 km
Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s
From the equation of motion,
v = u + at
a = v/t
or, 25/2×60
or, 5/24 m/s²
Distance covered is:
S = ut + 1/2 at²
= 0 + 1/2 x 5/24 x (120)²
= 1/2 x 5/24 x 120 x 120
= 1500 m
= 1.5 km