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alok12
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Asked: 2025-01-07T06:27:52+00:00 In:

A train moving with a velocity of 40m/s is brought to rest in 10 s. What is its acceleration?

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100%-2 m/s² ( 1 voter )
0%2 m/s²
0%-4 m/s²
0%4 m/s²
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This question requires the calculation of acceleration when the initial velocity, final velocity and time are given.

chapter 2. motion in straight lineclass 11th physicsclass 11th scienceexercise questionmcq based questionncert solutionshort answer
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    1 Answer

    1. Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 – 40/10 = -4m/s ²
      This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.

      For more please visit here:
      https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/

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