A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of ` 500 per m2. (Note that the base of the tent will not be covered with canvas.)

Height of cylindrical part (h) = 2.1 m
Diameter of cylindrical part = 4 m
Radius of cylindrical part (r) = 2 m
Height of conical part (l) = 2.8 m
Area of convas used = CSA conical part + CSA of cylindrical part
= πrl + 2πrh
= π × 2 × 2.8 + 2π × 2 × 2.1
= 2π(2.8 + 4.2) = 2 × (22/7) × 7 = 44m²
The Cost of 1 m² canvas = Rs500
Therefore, the cost of 44m² canvas = 44 × Rs.500 = Rs.22000.