A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8g mass.

Radius of larger cylinder (r₁) = 12 cm
Height of larger cylinder (h₁) = 220 cm
Radius of smaller cylinder (r₂) = 8 cm
Height of smaller cylinder (h₂) = 60 cm
Volume of pole = Volume of larger sylinder + Volume of smaller cylinder
= πr₁ ²h₁ + πr₂² h₂
=π(12)² 220 + π(8)² × 60
= π[144 × 220 + 64 × 60] = 3.14 35520 = 111532.8 cm³
Mass of 1 cm³ of iron = 8 g
Therefore, the mass of 111532.8 cm³ of iron
= 111532.8 × 8 g = 892262.4g = 892.262 kg