A scooter was bought at ₹ 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.

Here, Principal (P) = ₹ 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years
Amount (A) = P(1-R/100)ⁿ
= 42000(1-8/100)¹
= 42000(1+2/25)¹
= 42000(27/25)¹
= 42000 x 27/25 = ₹ 38,640
Hence, the value of scooter after one year is ₹ 38,640

Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video

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