Home/ Questions/Q 7157
Next
In Process
Ashok0210
  • 8
Asked: 2021-02-13T07:03:48+00:00 In:

A point charge causes an electric flux of –1.0 × 10³Nm²/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface? (b) What is the value of the point charge?

  • 8

Class-12th Physics,
Electric Charges and Fields,
Chapter-1, Exercise -1, Q-1.20
NCERT Solutions for Class 12th Physics

2020-2021cbsechapter 1class 12 physicsclass 12thclass 12th scienceelectric charges and fieldsncertncert solutionsphysics
Share

    1 Answer

    1. Ans (a).

      • Electric flux, Φ = —1.0 x 103 N m2/C and radius of the Gaussian surface, r = 10.0 cm Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., —103 N m2/C.
      • Ans (b).

      Electric flux is given by the relation

      Φ=q/ε0

      Where ε0 = Permittivity of free space = 8.854 x 10–12 N–1C2 m-2

       q = Net charge enclosed by the spherical surface = Φε0

      = -1.0 x 103 x 8.854 x 10–12 =-8.854 x 10–9C = -8.854 nC

      Therefore, the value of the point charge is -8.854 nC.

      • 0
    Leave an answer

    Leave an answer

    Browse