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alok12
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Asked: 2025-01-13T08:36:37+00:00 In:

A particle of mass 𝑚 is moving in a circular path of radius 𝑟 with constant speed 𝑣 . What is its angular momentum about the center of the circle?

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100%mvr ( 2 voters )
0%1/2mvr
0%mr²ω
0%2mvr
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This question evaluates angular momentum in circular motion.

Create multiple-choice questions (MCQs) for CBSE Class 11 Physics, Chapter 6: “System of Particles and Rotational Motion,” in line with the NCERT syllabus for 2024-2025. Focus on core topics like center of mass, torque, angular momentum and rotational dynamics. Include a variety of theoretical and numerical questions with varying difficulty levels to assess students’ understanding and problem-solving skills. Ensure clarity and alignment with NCERT standards to help students prepare effectively and reinforce key concepts in rotational motion.

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    1. In circular motion, angular momentum is 𝐿 = 𝑟⋅𝑚𝑣⋅sin 𝜃 = 90° , L=mvr.
      This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.

      For more please visit here:
      https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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