A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

Radius of right circular cone r = 7 cm and height h = 24 cm
Let, the slant height = l m
We know that l² = r² + h²
⇒ l² = 7² + 24² = 49 + 576 = 625
⇒ l = √625 = 25 cm
Area of sheet required to make 1 cap = πrl
= 22/7 ×7 × 25 = 550 cm²
Therefore, area of sheet required to make 10 such caps = 10 × 550 = 5500 cm²
Hence, area of sheet to make 10 such caps is 5500 cm²