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A hunter has a maching gun that can fire 50g bullets with a velocity of 150 ms⁻¹. A 60 kg tiger springs at him with a velocity of 10 ms⁻¹. How many bullets must the hunter fire into the target so as to stop him in his track ?

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1 Answer

  1. Given m = mass of bullet = 50 gm = 0.50 kg
    M = mass of tiger = 60 kg
    v = Velocity of bullet = 150 m/s
    V = Velocity of tiger = – 10m/s
    (∴ It is coming from opposite direction n = no. of bullets fired per second
    at the tiger so as to stop it.)
    Pi = 0, before firing …(i)
    Pf = n(mv) + MV …(ii)
    ∴ From the law of conservation of momentum,
    Pi = Pf
    ⇒ 0 = n(mv) + MV
    ⇒ n = MV/mv
    = -60/(-10)/0.05×150 = 80.

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