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A hockey ball of mass 200 g travelling at 10 m s–1 is struck bya hockey stick so as to return it along its original path with a velocity at 5 m s–1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

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NCERT Solutions for Class 9 Science Chapter 9
Force and Laws of Motion
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-129
Questions No-13

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1 Answer

  1. Mass of the hockey ball, m= 200 g = 0.2 kg
    Hockey ball travels with velocity, v₁= 10 m/s
    Initial momentum = mv₁
    Hockey ball travels in the opposite direction with velocity, v₂= -5 m/s
    Final momentum = mv₂
    Change in momentum = mv₁- mv₂= 0.2 [10 – (-5)] = 0.2 (15) = 3 kg m s⁻¹
    Hence, the change in momentum of the hockey ball is 3 kg m s⁻¹.

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-9/

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