NCERT Solutions for Class 10 Maths Chapter 13
Important NCERT Questions
Surface areas and Volumes,
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 13.1
Page No:244
Questions No:5
A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.
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The maximum daimeter of hemisphere = side of cubical block = l
Radius of hemisphere (r) = l/2
The surface area of the remaining solid
= TSA of cubical block + CSA of hemisphere – Area of base of hemisphere
= 6l² + 2πr² – πr²
= 6l² + πr²
= 6l² + π(l/2)²
= (6 + π/4)l²
Hence, the surface area of the remaining solid is (6 + π/4)l².
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