Asked: 2020-10-29T05:57:32+00:002020-10-29T05:57:32+00:00In: Class 10
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and these are equally likely outcomes. What is the probability that it will point at
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NCERT Solutions for Class 10 Maths Chapter 15
Important NCERT Questions
PROBABILITY
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 9.1
Page No:309
Questions No:12
Total number of possible outcomes = 8
(i) Probability of getting 8 = (Number of favorable outcomes)/(Number of total possible outcomes) = 1/8
(ii) Total number of odd numbers on spinner = 4
Probability of getting an odd number = (Number of favorable outcomes)/(Number of total possible outcomes) = 4/8 = 1/2
(iii) The numbers greater than 2 are 3, 4,5, 6, 7, and 8. Therefore, total numbers greater than 2 = 6
Probability of getting number greater than 2 = (Number of favorable outcomes)/(Number of total possible outcomes) = 6/8 = 3/4
(iv) The numbers less than 9 are 1, 2, 3, 4, 6, 7, and 8.
Therefore, total numbers less than 9 = 8
Probability of gettinga number less than 9 = 8/8 = 1
Total number of possible outcomes = 8
(i) Probability of getting 8 = (Number of favorable outcomes)/(Number of total possible outcomes) = 1/8
(ii) Total number of odd numbers on spinner = 4
Probability of getting an odd number = (Number of favorable outcomes)/(Number of total possible outcomes) = 4/8 = 1/2
(iii) The numbers greater than 2 are 3, 4,5, 6, 7, and 8. Therefore, total numbers greater than 2 = 6
Probability of getting number greater than 2 = (Number of favorable outcomes)/(Number of total possible outcomes) = 6/8 = 3/4
(iv) The numbers less than 9 are 1, 2, 3, 4, 6, 7, and 8.
Therefore, total numbers less than 9 = 8
Probability of gettinga number less than 9 = 8/8 = 1
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