NCERT Solutions for Class 10 Maths Chapter 13
Important NCERT Questions
Surface areas and Volumes,
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 13.4
Page No:257
Questions No:1
A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass.
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Radius of upper part of glass (r₁) = 4/2 = 2 cm
Radius of lower part of glass (r₂) = 2/2 = 1 cm
Height = 14 cm
Capacity of glass = Volume of frustum
= 1/3πh(r₁²+ r₂² + r₁r₂) = 1/3πh(2² + 1² + 2 × 1) = 1/3 × 22/7 × 14 × (7)
= 1/3 × 22 × 14 = 308/3 = 102(2/3)cm³.
Hence, the capacity of glass is 102(2/3)cm³.
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