A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? ( Take π = 3.14)

Diameter of the circular flower bed = 66 m
∴ Radius of circular flower bed (r) = 66/2 = 33 m
∴ Radius of circular flower bed with 4 m wide path (R) = 33 + 4 = 37 m
According to the question,
Area of path = Area of bigger circle – Area of smaller circle
= πR² – πr² = π(R²-r²)
= π[(37)²-(33)²
= 3.14 [ (37 + 33) (37 – 33)] [∵ a²-b²=(a+b)(a+b)]
= 3.14 x 70 x 4
= 879.20 m²
Therefore, the area of the path is 879.20 m².

Class 7 Maths Chapter 11 Exercise 11.3

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