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Sneha Thakur
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Asked: 2020-10-29T05:29:59+00:00 In:

A chord of a circle of radius 12 cm subtends an angle of 120° at the Centre. Find the area of the corresponding segment of the circle. (Use π= 3.14 and √3 = 1.73)

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NCERT Solutions for Class 10 Science Chapter 12
Important NCERT Questions
Areas Related To Circles Class,
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 12.2
Page No:230
Questions No:7

2020-2021areas related to circles classcbsechapter 12class10mathematicsncert
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    2 Answers

    1. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-12/

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    2. Best Answer
      A chord of a circle of radius 12 cm subtends an angle of 120° at the Centre. Find the area of the corresponding segment of the circle. (Use π= 3.14 and √3 = 1.73)

      The perpendicular OV drown form O to chord ST bisects ST.
      Therefore, SV = VT
      In △OVS,
      OV/OS = cos 60° ⇒ OV/12 = 1/2 ⇒ OV = 6 cm
      SV/OS = sin 60° ⇒ SV/12 = √3/2 ⇒ OV = 6√3 cm
      ST = 2 x SV = 2 x 6√3 = 12√3
      Area of △OST
      = 1/2 × ST × OV = 1/2 × 12√3 × 6 = 36√3 = 36 x 1.73 = 62.28 cm²
      Area of sector OSUT
      = 120°/360° x πr² = 1/3 x π(12)²
      = 1/3 x 3.14 x 12 x 12 = 150.72 cm²
      Area of minor segment
      = Area of sector OSUT – Area of △OST
      = (150.72 – 62.28) cm²
      = 88.44 cm²

      See here for video explanation👇😇

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