A chord of a circle of radius 10 cm subtends a right angle at the Centre. Find the area of the corresponding: (i) minor segment (ii) major sector. (Use π= 3.14)

(i) Let the chord AB subtends right angle at the centre O.
Area of segment with an angle 90°
= 90°/360° × πr² = 1/4 × π(10)² = 1/4 × 3.14 × 10 × 10 = 78.5 cm²
Area of triangle OAB
= 1/2 × OA × OB = 1/2 × 10 × 10 = 50 cm²
Area of minor segment = Area of minor sector Area of triangle OAB
= 78.5 cm² – 50 cm² = 28.5 cm²
(ii) Area of major segment = Area of cirlce Area of minor segment
= πr² – 1/4πr² = (1 – 1/4)πr² = 3/4πr²
= 3/4 × π(10)² = 3/4 × 3.14 × 10 × 10 = 235.5 cm²