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A chord of a circle of radius 10 cm subtends a right angle at the Centre. Find the area of the corresponding: (i) minor segment (ii) major sector. (Use π= 3.14)

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NCERT Solutions for Class 10 Maths Chapter 12
Important NCERT Questions
Areas Related To Circles Class,
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 12.2
Page No:230
Questions No:4

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2 Answers

  1. (i) Let the chord AB subtends right angle at the centre O.
    Area of segment with an angle 90°
    = 90°/360° × πr² = 1/4 × π(10)² = 1/4 × 3.14 × 10 × 10 = 78.5 cm²
    Area of triangle OAB
    = 1/2 × OA × OB = 1/2 × 10 × 10 = 50 cm²
    Area of minor segment = Area of minor sector Area of triangle OAB
    = 78.5 cm² – 50 cm² = 28.5 cm²
    (ii) Area of major segment = Area of cirlce Area of minor segment
    = πr² – 1/4πr² = (1 – 1/4)πr² = 3/4πr²
    = 3/4 × π(10)² = 3/4 × 3.14 × 10 × 10 = 235.5 cm²

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  2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-12/

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