Using the third equation of motion, the bullet acceleration is minus 10000 meters per second squared. Multiplying by the mass of 0.05 kilograms gives a retarding stopping force of 500 newtons acting opposite to motion.
A bullet of mass 50 g moving with a speed of 100 m s-1 enters a heavy stationary wooden block and stops after penetrating a distance of 50 cm. Estimate the stopping force acting on the bullet (assume that the bullet undergoes constant acceleration within the block).
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Given mass is 0.05 kilograms, initial velocity is 100 meters per second, final velocity is zero and displacement is 0.5 meters. Using the third kinematic formula, acceleration equals zero minus 10000 divided by twice 0.5, which is minus 10000 meters per second squared. From Newton second law, force equals mass times acceleration, giving 0.05 multiplied by 10000, yielding an opposing stopping force of 500 newtons.
For more NCERT Solutions of Class 9 Science Exploration Chapter 6 How Forces Affect Motion Question Answer (2026-27)
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