A body of mass π and radius π is rolling without slipping. What is the ratio of its translational kinetic energy to rotational kinetic energy?
This question explores the relationship between translational and rotational kinetic energies for rolling motion.
Create multiple-choice questions (MCQs) for CBSE Class 11 Physics, Chapter 6: “System of Particles and Rotational Motion,” based on the NCERT syllabus for the 2024-2025 academic session. Focus on key topics such as the center of mass, torque, angular momentum, rotational kinematics, dynamics and equilibrium. Ensure a diverse range of questions, including theoretical and numerical problems, to cater to varying difficulty levels and enhance critical thinking. The questions should be clear, concise and aligned with NCERT standards to help students grasp fundamental concepts and prepare effectively for examinations while reinforcing their overall understanding of the chapter.
For rolling without slipping, v = RΟ. Translational kinetic energy is 1/2MvΒ², and rotational kinetic energy is 1/2IΟΒ². Using I = 2/5MRΒ²(for a sphere), we find the ratio KEβα΅£ββββββα΅’ββββ : KEα΅£ββββα΅’ββββ = 2 : 1.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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