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Brinda
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Brinda
Asked: December 14, 20202020-12-14T06:35:39+00:00 2020-12-14T06:35:39+00:00In: Class 9 Science

A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate: (a) the net accelerating force; (b) the acceleration of the train; and (c) the force of wagon 1 on wagon 2.

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NCERT Solutions for Class 9 Science Chapter 9
Force and Laws of Motion
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-128
Questions No-7

2020-2021cbsechapter 9class 9 scienceclass9force and laws of motionncertscience
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    1. 9 PhysicsMaster
      2020-12-14T06:39:19+00:00Added an answer on December 14, 2020 at 6:39 am

      (a) 35000 N (b) 1.944 m/s² (c) 15552 N
      (a) Force exerted by the engine, F = 40000 N
      Frictional force offered by the track, Ff = 5000 N
      Net accelerating force, Fa = F – Ff = 40000 – 5000 = 35000 N
      Hence, the net accelerating force is 35000 N.
      (b) Acceleration of the train = a
      The engine exerts a force of 40000 N on all the five wagons.
      Net accelerating force on the wagons, Fa = 35000 N
      Mass of the wagons, m = Mass of a wagon × Number of wagons
      Mass of a wagon = 2000 kg
      Number of wagons = 5
      ∴ m = 2000 × 5 = 10000 kg
      Total mass (including the mass of engine), M = m + 8000 = 18000 kg
      Fa = Ma
      ⇒ 𝑎 = 𝐹𝑎/𝑀 = 35000/18000 = 1.944 𝑚/𝑠²
      (c) Mass of 4 wagons (excluding wagon 1) m = 2000 × 4 = 8000 kg
      Acceleration of the train = 1.944 𝑚/𝑠²
      ∴ The force of wagon 1 on wagon 2 = 𝑚𝑎 = 8000 × 1.944 = 15552 𝑁

      For more answers visit to website:
      https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-9/

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