NCERT Solutions for Class 9 Science Chapter 3
Atoms And Molecules
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Exercises Questions
Page No-43
Questions No- 1
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
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Mass of boron = 0.096g (Given)
Mass of oxygen = 0.144g (Given)
Mass of sample = 0.24g (Given)
Thus, percentage of boron by weight in the compound = 0.096×1000. / 24% = 40%
Thus, percentage of oxygen by weight in the compound = 0.144×1000./24%
= 60 %
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To determine the percentage composition by weight of the compound containing oxygen and boron, we’ll use the given masses of boron and oxygen in the sample.
Given:
– Mass of the compound = 0.24 g
– Mass of boron in the compound = 0.096 g
– Mass of oxygen in the compound = 0.144 g
Calculation for Percentage Composition:
1. Calculate the percentage of boron:
Percentage of boron = (Mass of boron / Total mass of compound) x 100
Percentage of boron = (0.096g / 0.24g) x 100
Percentage of boron = 40%
2. Calculate the percentage of oxygen:
Percentage of oxygen = (Mass of boron / Total mass of compound) x 100
Percentage of oxygen = (0.144g / 0.24g ) x 100
Percentage of oxygen = 60%
Summary:
– Percentage composition of the compound by weight:
– Boron: 40%
– Oxygen: 60%
Therefore, in the given compound of oxygen and boron, the weight percentage composition is 40% boron and 60% oxygen.