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Asked: 2021-03-23T09:47:50+00:00 In:

∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e., CE?

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∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e., CE?

NCERT Solutions for Class 7 Mathematics Chapter 11
Important NCERT Questions
Class vii Math Chapter 11 Perimeter and Area Exercise 11.2
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 8

2020-2021cbsechapter 11class7mathematicsncertperimeter and area
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      In ∆ABC, AD = 6 cm and BC = 9 cm
      Area of triangle = 1/2 x base x height = 1/2 x BC x AD
      = 1/2 x 9 x 6 = 27 cm²
      Again, Area of triangle = 1/2 x base x height = 1/2 x AB x CE
      ⇒ 27 = 1/2 x 7.5 x CE
      ⇒ CE = 27×2/7.5
      ⇒ CE = 7.2 cm
      Thus, height from C to AB i.e., CE is 7.2 cm.

      Class 7 Maths Chapter 11 Exercise 11.2

      for more answers vist to:
      https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-11/

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