∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e., CE?

In ∆ABC, AD = 6 cm and BC = 9 cm
Area of triangle = 1/2 x base x height = 1/2 x BC x AD
= 1/2 x 9 x 6 = 27 cm²
Again, Area of triangle = 1/2 x base x height = 1/2 x AB x CE
⇒ 27 = 1/2 x 7.5 x CE
⇒ CE = 27×2/7.5
⇒ CE = 7.2 cm
Thus, height from C to AB i.e., CE is 7.2 cm.

Class 7 Maths Chapter 11 Exercise 11.2

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