P = P₁ + P2 = (+ 6 D) + (-2D) = + 4 D Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
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When tha concave lens of refractive index 1.5 (ng = 1.5) is immersed in a midium of refractive index 1.65 (nm = 1.65), the lens begins to behave as a converging (convex) lens. Class 12 Physics Chapter 9 Ray Optics ...
Refractive index of liquid should be 1.5. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
Here P = P₁ + P2 = (-4 D) + (2 D) = -2D Hence, f = 1/p = – 1/2 m = -50 cm. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
The focal length of the given convex lens is 20 cm. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
Let focal length of converging lens f₁ = + f and focal length of diverging lens f₂ = -f. If focal length of combination be feq, then 1/feq = 1/f1 + 1/f2 = 1/(+f) + 1/(-f) = 0 feq = ...
The lens will now behave as a converging lens because its new refractive index w.r.t. water is less than one. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
The lens will disappear and there will be no converging or diverging action of the lens. Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
The power of given convex lens increases on account of the fact that fv < fr Class 12 Physics Chapter 9 Ray Optics and Optical Instruments Session 2024-2025.
As the glass lens of refractive index n = 1.45 disappears when immersed in a liquid, hence refractive index of liquid must be same as that of lens. ∴ Refractive index of liquid = 1.45. Class 12 Physics Chapter 9 ...