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The sum of k consecutive natural numbers is k(2a + k – 1) / 2 = 100, meaning k(2a + k – 1) = 200. Testing odd factors gives only k = 5, yielding 18 + 19 + 20 + ...

all possible ways of expressing 100cbse class 9 ganita manjari chapter 8 solutionscbse internal assessmentcbse notesexpressing 100 as the sum of consecutive natural numbershalf yearly exam question paper – class 9 math exploring sequences and progressionssample question from class 9 chapter predicting what comes next
Virat
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The bounce heights form a GP with first term 48 metres and common ratio 0.6. Therefore, the fifth bounce height is 48 multiplied by 0.6 raised to 4, which equals 6.2208 metres. Hence, the required height is 6.2208 metres.

ball is dropped from a height of 80 metresbounces back to 60% of the heightcbse class 9 ganita manjari chapter 8 exercise 8.3 solutionsncert class 9 ganita manjari chapter 8 exercise 8.3 questions answersample question from class 9 chapter predicting what comes nexttotal vertical distance the ball has travelled