The bounce heights form a GP with first term 48 metres and common ratio 0.6. Therefore, the fifth bounce height is 48 multiplied by 0.6 raised to 4, which equals 6.2208 metres. Hence, the required height is 6.2208 metres.
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The first term is 2 and the common ratio is 3. The explicit formula is tn equals 2 multiplied by 3 raised to n minus 1. Since 4374 equals 2 multiplied by 3 raised to 7, it is the eighth ...
The 8th term is 192 and the common ratio is 2. From the 8th term to the 12th term there are four steps. Therefore, t12 equals 192 multiplied by 2 four times, giving 3072.