The smallest 4-digit number divisible by 3, 5, and 7 is 1050. It is a multiple of their least common multiple (LCM = 105) and the smallest such number exceeding 1000. class 6 Mathematics Textbook Chapter 5 question answer class 6 Mathematics ...
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168 is divisible by 12. The prime factorization of 168 is 2³ × 3 × 7, and 12 is 2² × 3. All factors of 12 are included in 168’s factorization. Class 6 Mathematics Chapter 5 Prime Time question answer Class 6 ...
Prime factorization means expressing a number as a product of its prime factors. For example, 18 = 2 ×3². It breaks numbers into their smallest building blocks, which are prime numbers. 141: 3 × 47, 1728: 2⁶ × 3³, 1024: ...
From 2024 to 2099, leap years are those divisible by 4. These include 2024, 2028, 2032, …, 2096. Counting these, there are 19 leap years in this range. Class 6 Mathematics Chapter 5 Prime Time question answer Class 6 NCERT Ganita Prakash ...
The smallest 4-digit palindrome divisible by 4 is 2002, and the largest is 9999. Both numbers meet the conditions for divisibility and being palindromes when checked through divisibility tests. class 6 Mathematics Textbook Chapter 5 question answer class 6 Mathematics Chapter 5 ...
Only 5600, 6000, and 77622160 are divisible by all. Divisibility by 2, 4, 5, 8, and 10 requires multiples of their least common multiple (LCM), 40. These numbers meet the criteria. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 ...
The two numbers are 8 and 5. Divisibility by 8 confirms divisibility by 2 and 4. Divisibility by 5 ensures divisibility by 10. Hence, checking these two guarantees divisibility by all. Class 6 NCERT Ganita Prakash Chapter 5 Prime Time class 6 ...
Three pairs of prime numbers under 20 with sums as multiples of 5 are: (2, 3), (7, 13), and (11, 19). Their sums are 5, 20, and 30, respectively, all divisible by 5. Class 6 Mathematics Ganita Prakash Prime Time Class 6 ...
No, 2 is the only even prime number. All other even numbers are divisible by 2, making them composite. Prime numbers have only two divisors, 1 and themselves, which excludes all other even numbers. Class 6 Mathematics Ganita Prakash Prime Time Class ...
The numbers 7 and 8 satisfy the condition. Their least common multiple (LCM) is 56, which exceeds 50. Both numbers are under 10 and their LCM is calculated as (7 × 8 ÷ 1). Class 6 NCERT Ganita Prakash Chapter 5 ...