The magnetic field due to a straight current-carrying wire is given by B = μ0I/2πr. Substituting μ0 4π × 10⁻⁷, I = 10 A and r = 0.1 m, B = 2 × 10⁻⁵ T. Using the right-hand rule, ...
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Sanjay01 Kumar
Asked: In: Class 12 Physics
In a parallel circuit, power P = V²/R. Since both resistors have the same voltage, the thermal energy ratio is inversely proportional to resistance. Thus, E100Ω : E 200Ω = 200 : 100 = 2:1. Answer: (b) 2:1.
Sanjay01 Kumar
Asked: In: Class 12 Physics
Using the formula for parallel battery circuits: V = 12/1 + 13/2 /1/1 + 1/2 = 12 + 6.5/1.5 = 11.67V Thus, the answer is (a) 11.6 V to 11.7 V.
Sanjay01 Kumar
Asked: In: Class 12 Physics
Let the emfs be E₁ and E₂. From the potentiometer principle: E₁ + E₂/E₁ – E₂ = 50/10 = 5 Solving, E₁/E₂ = 5/1. Answer: (d) 5:1.
Sanjay01 Kumar
Asked: In: Class 12 Physics
Using P = V²R/(R+r)² , equating power for R = 4Ω and R = 1Ω, solving gives r = 2Ω and E = 12V. Maximum power = 18W. Answer: (c).