Given, initial velocity u = 0, final velocity v = 24 m s⁻¹ and time t = 6 s. Average acceleration = (24 − 0)/6 = 4 m s⁻². Distance = ½(0 + 24) × 6 = 72 m.
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Yes, the ball undergoes straight-line motion along the inclined track. Its motion can be represented by a horizontal line. Since the ball moves in one direction without reversing, total distance and displacement magnitude are equal at A, B, C and ...