We take out the common factor 1/5 from the entire expression. The remaining polynomial inside is 9s square + 30sv + 25v square, which condenses smoothly into (3s + 5v) square.
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This polynomial fits the standard identity a square + 2ab + b square. We rewrite 4s square as (2s) square and 25t square as (5t) square, giving the factored result of (2s + 5t) square.
Ayushree
Asked: In: Class 9 Maths
We substitute a = 1/x and b = 1/y into the identity. Finding the squares of these fractional variables and combining their cross-product gives the final simplified rational terms.
Ayushree
Asked: In: Class 9 Maths
We use the identity with a = 7/5 x and b = 3/2 y. Squaring the fractional coefficients and multiplying two with both terms yields the expanded expression with simplified fraction terms.