The correct answer is (D) 6 A in the clockwise direction. To nullify the magnetic field at the common center, the magnetic fields produced by both loops must be equal and opposite. Using the ratio of radii and currents, loop ...
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Sanjay01 Kumar
Asked: In: Class 12 Physics
The resistance of each lamp is R = V/P = 100/50 = 200Ω. Let n be the number of lamps. The total resistance in parallel is: 1/Req = n/200 Including battery resistance: Rtotal = 200/n + 10 For full power:
Sanjay01 Kumar
Asked: In: Class 12 Physics
Given: Supply voltage = 120V, Lead wire resistance = 6Ω, Bulb power = 60W, Heater power = 240W. using R = V²/P, Bulb resistance = 240, Heater resistance = 60Ω. Current before: 0.5A, Current after: 2.5A. Voltage drop increase: 12V.
(2022-2023) CBSE Chapter 1 Class 12 Electric Charge and Fields Physics NCERT
Ashok0210
Asked: In: Class 12 Physics
Class-12th Physics, CBSE and UP Board Electric Charges and Fields, Chapter-1, Exercise -1, Q-1.1 NCERT Solutions for Class 12th Physics