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Home/chapter 9 atomic foundations of matter solutions

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Virat
Virat
Asked: September 9, 2026In: Class 9 Science

A particular element A has one electron in its third shell. There is another element B with six electrons in its second shell. (i) How many electrons does A tend to give or take to become stable? (ii) What kind of ion would it form? (iii) How many electrons does B tend to give or take to become stable? (iv) What kind of ion would it form? (v) If A and B were to combine, what kind of bond would be formed? (vi) What would be the formula for the compound thus formed?

Element A loses one electron to form a unipositive cation A+. Element B gains two electrons to form a dipositive anion B2-. They combine through an ionic bond to form the compound A2B.

chapter 9 atomic foundations of matter solutionshalf yearly exam question paper - atomic foundations of matterhow many electrons does a tend to give or take to become stable?ncert solutions - atomic foundations of matterparticular element a has one electron in its third shell
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    Kriti added an answer Element A has one valence electron, so it loses one… September 9, 2026 at 7:11 am
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    Kriti added an answer Option (iii) is the correct answer. In this combination, two… September 9, 2026 at 7:11 am
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    Kriti added an answer Statement (iv) is correct because water contains two hydrogen atoms… September 9, 2026 at 7:11 am
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    Kriti added an answer Aluminium ion Al3+ combines with nitrate NO3- to give aluminium… September 9, 2026 at 7:11 am

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