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Ayushree
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Using the identity (a+1)² = a² + 2a + 1, 126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251. So, the correct option is (iv) 15625 + 251. Class 8 NCERT Ganita Prakash ...

a square and a cube class 8 problems and solutionsclass 8 maths chapter 1 a square and a cube figure it out solutionswhat is the value of 126²
Ayushree
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Prime factorisation of 1323 = 3³ × 7². To make it a cube, we need one more 7. So, multiply by 7. 1323 × 7 = 9261 and 9261 = 21³. So, required number = 7. Class 8 Mathematics Textbook Chapter ...

a square and a cube class 8 problems and solutionsganita prakash grade 8 a square and a cube solutionsnumber will you multiply by 1323 to make it a cube number
Ayushree
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Yes, we can definitely say this. No square number ends in 2, 3, 7 or 8. So, if a number ends with any of these digits, it cannot be a perfect square. This rule helps quickly eliminate such numbers. Class 8 ...

–37 or 8a square and a cube class 8 problems and solutionsclass 8 maths chapter 1 a square and a cube figure it out solutionsnumber ends with 2then we can definitely say that it is not a square