Starting with t1 equal to 2, the recursive rule gives the sequence 2, 4, 10, 28, 82, 244, 730. Therefore, 730 occurs at the seventh position. Hence, 730 is the seventh term of the sequence.
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The first term is 5 and the common ratio is 5. Using the GP formula, tn equals a multiplied by r raised to n minus 1. Therefore, tn equals 5 raised to n. The 10th term is 9765625.
Virat
Asked: In: Class 9 Maths
The 8th term is 192 and the common ratio is 2. From the 8th term to the 12th term there are four steps. Therefore, t12 equals 192 multiplied by 2 four times, giving 3072.
12th term of a gp with common ratio 2cbse class 9 ganita manjari chapter 8 exercise 8.3 solutionsclass 9 ganita manjari chapter 8 step by step solutionsncert class 9 ganita manjari chapter 8 exercise 8.3 questions answerpredicting what comes next: exploring sequences and progressions solutions class 9
Kriti
Asked: In: Class 9 Maths
The marble counts represent the sum of the first 25 natural numbers. Using the sum formula Sn = n(n + 1) / 2 with n = 25, the total calculation is 25 x 26 / 2, which gives 325 marbles.
arranges marbles in rows so that the first row has 1 marblecbse class 9 ganita manjari chapter 8 exercise 8.2 solutionsclass 9 ganita manjari chapter 8 exercise solutions (2026-27)class 9 ganita manjari chapter 8 question answerhow many marbles does the child use in allpredicting what comes next: exploring sequences and progressions solutions
Kriti
Asked: In: Class 9 Maths
With initial salary of 5,00,000 and annual increment of 20,000, his earnings form an AP. Solving 7,00,000 = 5,00,000 + (n – 1) x 20,000 gives n = 11, meaning his income reaches 7,00,000 after 10 years.
00000cbse class 9 ganita manjari chapter 8 exercise 8.2 solutionsclass 9 ganita manjari chapter 8 step by step solutionsganita manjari chapter 8 exercise solutions class 9 (2026-27)how many years did his income reach ₹7ncert solutions – predicting what comes next: exploring sequences and progressionsstarted work at an annual salary of ₹5