For four identical resistors in parallel, the effective resistance is: R/4 = 0.25 ⇒ R = 1Ω In series, total resistance is: R series= 4R = 4 × 1 = 4Ω Thus, the correct answer is (a) 4 Ω.
Category: Class 12 Physics
NCERT Solutions for Class 12 Physics updated for CBSE academic session 2021-2022.
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