(-5) + (-8) = (-8) + (-5) [Commutative property] Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Team A scored -40,10,0 Total score of Team A = -40+10+0 =-30 Team B scored 10,0,-40 Total score of Team B = 10+0+(-40) = 10 + 0 - 40 = -30 Thus, scores of both teams are same. Yes, we can add integers in any order due to commutative property. Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for moreRead more
Team A scored -40,10,0
Total score of Team A = -40+10+0 =-30
Team B scored 10,0,-40
Total score of Team B = 10+0+(-40) = 10 + 0 – 40 = -30
Thus, scores of both teams are same.
Yes, we can add integers in any order due to commutative property.
(a) -2-(-10)-2+10=8 (b) (-7)+2=-5 (c) (-2)-1=-2-1=-3 Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(a) One such pair whose sum is -7: -5+(-2)=-7 (b) One such pair whose difference is -10: -2-8=-10 (c) One such pair whose sum is 0: -5+5 = 0 Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(a) One such pair whose sum is -7: -5+(-2)=-7
(b) One such pair whose difference is -10: -2-8=-10
(c) One such pair whose sum is 0: -5+5 = 0
(i) a=21,b=18 Given: a=21,b=18 We have a-(-b) = a + b Putting the values in L.H.S. = a-(-b)= 21-(-18) = 21+18 =39 Putting the values in R.H.S. = a + b = 21 + 19 = 39 Since, L.H.S. = R.H.S Hence, verified. (ii) Given: a = 118,b = 125 We have a-(-b)=a+b Putting the values in L.H.S. = a-(-b) = 118 = (-Read more
(i) a=21,b=18
Given: a=21,b=18
We have a-(-b) = a + b
Putting the values in L.H.S. = a-(-b)= 21-(-18) = 21+18 =39
Putting the values in R.H.S. = a + b = 21 + 19 = 39
Since, L.H.S. = R.H.S
Hence, verified.
(ii) Given: a = 118,b = 125
We have a-(-b)=a+b
Putting the values in L.H.S. = a-(-b) = 118 = (-125) = 118+125 =243
Putting the values in R.H.S. = a+b = 118 + 125 = 243
Since, L.H.S. = R.H.S
Hence, verified.
Fill in the blanks to make the following statements true: (-5) + (-8) = (-8) + (…….)
(-5) + (-8) = (-8) + (-5) [Commutative property] Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(-5) + (-8) = (-8) + (-5) [Commutative property]
Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
In a quiz, team A scored – 40,10,0 and team B scores 10, 0, -40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?
Team A scored -40,10,0 Total score of Team A = -40+10+0 =-30 Team B scored 10,0,-40 Total score of Team B = 10+0+(-40) = 10 + 0 - 40 = -30 Thus, scores of both teams are same. Yes, we can add integers in any order due to commutative property. Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for moreRead more
Team A scored -40,10,0
Total score of Team A = -40+10+0 =-30
Team B scored 10,0,-40
Total score of Team B = 10+0+(-40) = 10 + 0 – 40 = -30
Thus, scores of both teams are same.
Yes, we can add integers in any order due to commutative property.
Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(a) Write a pair of negative integers whose difference gives 8. (b) Write a negative integer and a positive integer whose is -5. (c) Write a negative integer and a positive integer whose difference is -3.
(a) -2-(-10)-2+10=8 (b) (-7)+2=-5 (c) (-2)-1=-2-1=-3 Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(a) -2-(-10)-2+10=8
(b) (-7)+2=-5
(c) (-2)-1=-2-1=-3
Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Write down a pair of integers whose: (a) sum is -7 (b) difference is -10 (a) sum is 0
(a) One such pair whose sum is -7: -5+(-2)=-7 (b) One such pair whose difference is -10: -2-8=-10 (c) One such pair whose sum is 0: -5+5 = 0 Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4 for more answers vist to: https://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
(a) One such pair whose sum is -7: -5+(-2)=-7
(b) One such pair whose difference is -10: -2-8=-10
(c) One such pair whose sum is 0: -5+5 = 0
Class 7 Maths Exercise 1.2 Questions 1, 2, 3, 4
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/
Verify a-(-b) = a+b for the following values of and a : b (i) a=21,b=18 (ii) a=118,b=125
(i) a=21,b=18 Given: a=21,b=18 We have a-(-b) = a + b Putting the values in L.H.S. = a-(-b)= 21-(-18) = 21+18 =39 Putting the values in R.H.S. = a + b = 21 + 19 = 39 Since, L.H.S. = R.H.S Hence, verified. (ii) Given: a = 118,b = 125 We have a-(-b)=a+b Putting the values in L.H.S. = a-(-b) = 118 = (-Read more
(i) a=21,b=18
Given: a=21,b=18
We have a-(-b) = a + b
Putting the values in L.H.S. = a-(-b)= 21-(-18) = 21+18 =39
Putting the values in R.H.S. = a + b = 21 + 19 = 39
Since, L.H.S. = R.H.S
Hence, verified.
(ii) Given: a = 118,b = 125
We have a-(-b)=a+b
Putting the values in L.H.S. = a-(-b) = 118 = (-125) = 118+125 =243
Putting the values in R.H.S. = a+b = 118 + 125 = 243
Since, L.H.S. = R.H.S
Hence, verified.
7 Maths Chapter 1 Exercise 1.1 Question 7, 8
for more answers vist to:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-7/maths/chapter-1/