1. The 36th odd number can be found using the formula for the nth odd number, which is 2n – 1. So, 2 × 36 = 72 and subtracting 1 gives 71. Thus, the 36th odd number is 71. This method is useful when calculating squares by summing consecutive odd numbers, like 1 + 3 + 5 + … + 71 to get the square of 36,Read more

    The 36th odd number can be found using the formula for the nth odd number, which is 2n – 1. So, 2 × 36 = 72 and subtracting 1 gives 71. Thus, the 36th odd number is 71. This method is useful when calculating squares by summing consecutive odd numbers, like 1 + 3 + 5 + … + 71 to get the square of 36, which is 1296.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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  2. To find the nth odd number, we use the formula 2n – 1. This means if you want the 5th odd number, it would be 2×5 – 1 = 9. This formula is important because square numbers are formed by the sum of the first n odd numbers. For example, the sum of the first 4 odd numbers (1 + 3 + 5 + 7) equals 16, whiRead more

    To find the nth odd number, we use the formula 2n – 1. This means if you want the 5th odd number, it would be 2×5 – 1 = 9. This formula is important because square numbers are formed by the sum of the first n odd numbers. For example, the sum of the first 4 odd numbers (1 + 3 + 5 + 7) equals 16, which is 4².

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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    • 107
  3. From 1 to 100, the square numbers are 1² to 10², totaling 10 numbers. From 101 to 200, we have 11² = 121 to 14² = 196, totaling 4 square numbers. As numbers increase, the number of square numbers in each 100-block reduces. The largest perfect square below 1000 is 961, which is 31². This shows how sqRead more

    From 1 to 100, the square numbers are 1² to 10², totaling 10 numbers. From 101 to 200, we have 11² = 121 to 14² = 196, totaling 4 square numbers. As numbers increase, the number of square numbers in each 100-block reduces. The largest perfect square below 1000 is 961, which is 31². This shows how square numbers grow and spread across number ranges.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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    • 35
  4. There is a pattern where the sum of two consecutive triangular numbers equals a perfect square. Triangular numbers like 1, 3, 6, 10 and 15 when paired successively give squares: 1+3=4, 3+6=9, 6+10=16, 10+15=25. This means the next term would be 15+21 = 36 (6²). This connection reveals how triangularRead more

    There is a pattern where the sum of two consecutive triangular numbers equals a perfect square. Triangular numbers like 1, 3, 6, 10 and 15 when paired successively give squares: 1+3=4, 3+6=9, 6+10=16, 10+15=25. This means the next term would be 15+21 = 36 (6²). This connection reveals how triangular and square numbers are related through addition, showing beautiful patterns in number theory.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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    • 96
  5. To find the side of a square from its area, we take the square root of the area. Given the area is 49 sq. cm, we find √49 = 7. This is because 7 × 7 = 49. Therefore, the length of each side of the square is 7 cm. This method is used whenever we know the area and want to determine the side length ofRead more

    To find the side of a square from its area, we take the square root of the area. Given the area is 49 sq. cm, we find √49 = 7. This is because 7 × 7 = 49. Therefore, the length of each side of the square is 7 cm. This method is used whenever we know the area and want to determine the side length of a square.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

     

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