1. To find 126² using 125², apply the identity: (a+1)² = a² + 2a + 1 Here, a = 125, so 126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251 Therefore, the correct option is (iv) 15625 + 251. This method allows quick calculations using known square values and avoids complete re-multiplication.  Read more

    To find 126² using 125², apply the identity:
    (a+1)² = a² + 2a + 1
    Here, a = 125, so
    126² = 125² + 2×125 + 1 = 15625 + 250 + 1 = 15625 + 251
    Therefore, the correct option is (iv) 15625 + 251. This method allows quick calculations using known square values and avoids complete re-multiplication.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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  2. Let’s compute the squares: 64² = 4096 (last digit is 6) 108² = 11664 (last digit is 4) 292² = 85264 (last digit is 4) 36² = 1296 (last digit is 6) Among these, only 108² and 292² end in 4. So, the correct options with a unit digit 4 are 108² and 292². The question asks for which square ends in 4 andRead more

    Let’s compute the squares:
    64² = 4096 (last digit is 6)
    108² = 11664 (last digit is 4)
    292² = 85264 (last digit is 4)
    36² = 1296 (last digit is 6)
    Among these, only 108² and 292² end in 4. So, the correct options with a unit digit 4 are 108² and 292². The question asks for which square ends in 4 and both satisfy it.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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    • 7
  3. Among the given numbers, only 1089 is a perfect square (33² = 1089). The other numbers—2032, 2048 and 1027—are not perfect squares because they don’t have whole number square roots. If you try to factor or estimate their roots, you'll find they lie between squares, proving they’re not perfect squareRead more

    Among the given numbers, only 1089 is a perfect square (33² = 1089). The other numbers—2032, 2048 and 1027—are not perfect squares because they don’t have whole number square roots. If you try to factor or estimate their roots, you’ll find they lie between squares, proving they’re not perfect squares. So, the correct answer is: Only 1089 is a perfect square; the rest are not.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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    • 73
  4. Akhil cannot cut a 15 cm × 15 cm square from 125 cm² because 15² = 225, which exceeds the cloth’s area. The largest square he can cut must have an area less than or equal to 125. The closest perfect square less than 125 is 121 and √121 = 11. So, the biggest square handkerchief with an integer side tRead more

    Akhil cannot cut a 15 cm × 15 cm square from 125 cm² because 15² = 225, which exceeds the cloth’s area. The largest square he can cut must have an area less than or equal to 125. The closest perfect square less than 125 is 121 and √121 = 11. So, the biggest square handkerchief with an integer side that Akhil can cut is 11 cm × 11 cm.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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  5. Since 250 is not a perfect square, Bijou can estimate the square root. 15² = 225 and 16² = 256. So, √250 must lie between 15 and 16. Since 250 is closer to 256 than to 225, we can estimate that √250 ≈ 15.8 or just say it is slightly less than 16. This approximation is useful when exact roots are notRead more

    Since 250 is not a perfect square, Bijou can estimate the square root. 15² = 225 and 16² = 256. So, √250 must lie between 15 and 16. Since 250 is closer to 256 than to 225, we can estimate that √250 ≈ 15.8 or just say it is slightly less than 16. This approximation is useful when exact roots are not available for non-square numbers.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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