1. The given construction forms an obtuse-angled triangle. In an obtuse-angled triangle, the perpendicular bisectors of the sides intersect at a point outside the triangle. This point is called the circumcentre. A circle drawn with this point as the centre passes through all three vertices of the trianRead more

    The given construction forms an obtuse-angled triangle. In an obtuse-angled triangle, the perpendicular bisectors of the sides intersect at a point outside the triangle. This point is called the circumcentre. A circle drawn with this point as the centre passes through all three vertices of the triangle. Hence, the circumcentre lies outside the triangle.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

     

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  2. The circumcentre is the point where the perpendicular bisectors of the triangle meet. It is equally distant from all three vertices. Therefore, the lengths of OA, OB and OC are equal. When measured with a ruler, the three distances should be the same. Any slight variation is usually caused by smallRead more

    The circumcentre is the point where the perpendicular bisectors of the triangle meet. It is equally distant from all three vertices. Therefore, the lengths of OA, OB and OC are equal. When measured with a ruler, the three distances should be the same. Any slight variation is usually caused by small construction or measurement errors.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

     

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  3. Infinitely many circles can pass through two given points. Among them, the smallest circle is formed when the two points become the endpoints of the diameter. In this case, the centre lies at the midpoint of the line segment joining the points. Therefore, the least possible radius is equal to half tRead more

    Infinitely many circles can pass through two given points. Among them, the smallest circle is formed when the two points become the endpoints of the diameter. In this case, the centre lies at the midpoint of the line segment joining the points. Therefore, the least possible radius is equal to half the distance between the two given points.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  4. No point can be equally distant from three collinear points. The perpendicular bisectors of AB and BC remain parallel, so they never meet to form a circumcentre. Without a common circumcentre, a circle cannot pass through all three collinear points. Also, a straight line can intersect a circle at aRead more

    No point can be equally distant from three collinear points. The perpendicular bisectors of AB and BC remain parallel, so they never meet to form a circumcentre. Without a common circumcentre, a circle cannot pass through all three collinear points. Also, a straight line can intersect a circle at a maximum of two distinct points, never at three distinct points.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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  5. Yes, it is possible to construct other triangles congruent to the given triangle on the same circumcircle. These triangles have identical side lengths and angles but occupy different positions on the circle. Although their orientation changes, they remain congruent and share the same circumcircle.Read more

    Yes, it is possible to construct other triangles congruent to the given triangle on the same circumcircle. These triangles have identical side lengths and angles but occupy different positions on the circle. Although their orientation changes, they remain congruent and share the same circumcircle.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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