Option iii is correct. Assertion A is true because scattering of light occurs in colloids and suspensions but not in transparent solutions. Reason R is false because particles in a solution are the smallest, having a diameter less than 1 nm. Therefore, they cannot scatter light sufficiently to produRead more
Option iii is correct. Assertion A is true because scattering of light occurs in colloids and suspensions but not in transparent solutions. Reason R is false because particles in a solution are the smallest, having a diameter less than 1 nm. Therefore, they cannot scatter light sufficiently to produce the Tyndall effect. The statement that solution particles are larger than 100 nm is incorrect.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
Yes, cooking oil and water form two separate layers because they are immiscible liquids. One litre of oil has a mass of 910 g, so it is less dense than water. Therefore, oil forms the upper layer and water forms the lower layer. The layers can be separated using a separating funnel by opening the stRead more
Yes, cooking oil and water form two separate layers because they are immiscible liquids. One litre of oil has a mass of 910 g, so it is less dense than water. Therefore, oil forms the upper layer and water forms the lower layer. The layers can be separated using a separating funnel by opening the stopcock to collect the lower water layer first, followed by oil.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
(i) Total mass is 75 + 420 + 5 = 500 g. Sugar concentration is 75/500 × 100 = 15 percent, flour is 420/500 × 100 = 84 percent and sodium hydrogencarbonate is 5/500 × 100 = 1 percent. (ii) Copper = 70/100 × 120 = 84 g. Zinc = 120 − 84 = 36 g. For more NCERT Solutions of Class 9 Science ExploraRead more
(i) Total mass is 75 + 420 + 5 = 500 g. Sugar concentration is 75/500 × 100 = 15 percent, flour is 420/500 × 100 = 84 percent and sodium hydrogencarbonate is 5/500 × 100 = 1 percent. (ii) Copper = 70/100 × 120 = 84 g. Zinc = 120 − 84 = 36 g.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
For car A, acceleration = (5−0)/5 = 1 m s⁻². Its displacement in 5 s = ½ × 1 × 5² = 12.5 m. For car B, acceleration = (3−0)/10 = 0.3 m s⁻². Its displacement in 10 s = ½ × 0.3 × 10² = 15 m. Thus, both velocity-time graphs are straight lines starting from the origin, with slopes 1 and 0.3 m s⁻², respeRead more
For car A, acceleration = (5−0)/5 = 1 m s⁻². Its displacement in 5 s = ½ × 1 × 5² = 12.5 m. For car B, acceleration = (3−0)/10 = 0.3 m s⁻². Its displacement in 10 s = ½ × 0.3 × 10² = 15 m. Thus, both velocity-time graphs are straight lines starting from the origin, with slopes 1 and 0.3 m s⁻², respectively.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
For the first 2 minutes = 120 s, the car moves at 6 m s⁻¹. Therefore, displacement = 6 × 120 = 720 m. During the next 6 s, initial velocity is 6 m s⁻¹ and acceleration is 1 m s⁻². Displacement = ut + ½at² = 6 × 6 + ½ × 1 × 36 = 54 m. Hence, total displacement = 720 + 54 = 774 m. For more NCERRead more
For the first 2 minutes = 120 s, the car moves at 6 m s⁻¹. Therefore, displacement = 6 × 120 = 720 m. During the next 6 s, initial velocity is 6 m s⁻¹ and acceleration is 1 m s⁻². Displacement = ut + ½at² = 6 × 6 + ½ × 1 × 36 = 54 m. Hence, total displacement = 720 + 54 = 774 m.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
Assertion (A): Solutions do not exhibit the Tyndall effect. Reason (R): The particles in solutions are larger than 100 nm, so they cannot scatter light. Choose the correct option: (i) Both A and R are true and R is the correct explanation of A. (ii) Both A and R are true, but R is not the correct explanation of A. (iii) A is true, but R is false. (iv) A is false, but R is true.
Option iii is correct. Assertion A is true because scattering of light occurs in colloids and suspensions but not in transparent solutions. Reason R is false because particles in a solution are the smallest, having a diameter less than 1 nm. Therefore, they cannot scatter light sufficiently to produRead more
Option iii is correct. Assertion A is true because scattering of light occurs in colloids and suspensions but not in transparent solutions. Reason R is false because particles in a solution are the smallest, having a diameter less than 1 nm. Therefore, they cannot scatter light sufficiently to produce the Tyndall effect. The statement that solution particles are larger than 100 nm is incorrect.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-5/
See lessThe label on a cooking oil pack says one litre (910 g). If this oil is mixed with water, will it form a separate layer? If so, which substance will be on top? How will you separate the two layers? Also, draw the diagram of the apparatus used.
Yes, cooking oil and water form two separate layers because they are immiscible liquids. One litre of oil has a mass of 910 g, so it is less dense than water. Therefore, oil forms the upper layer and water forms the lower layer. The layers can be separated using a separating funnel by opening the stRead more
Yes, cooking oil and water form two separate layers because they are immiscible liquids. One litre of oil has a mass of 910 g, so it is less dense than water. Therefore, oil forms the upper layer and water forms the lower layer. The layers can be separated using a separating funnel by opening the stopcock to collect the lower water layer first, followed by oil.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-5/
See lessSolve the following problems: (i) A cake recipe uses dry ingredients, namely 75 g of sugar for 420 g of all-purpose flour and 5 g of sodium hydrogencarbonate. Express the concentration of each component in the mixture using an appropriate method. (ii) A brass alloy contains 70% copper by mass. Calculate the quantities of copper and zinc present in 120 g of brass.
(i) Total mass is 75 + 420 + 5 = 500 g. Sugar concentration is 75/500 × 100 = 15 percent, flour is 420/500 × 100 = 84 percent and sodium hydrogencarbonate is 5/500 × 100 = 1 percent. (ii) Copper = 70/100 × 120 = 84 g. Zinc = 120 − 84 = 36 g. For more NCERT Solutions of Class 9 Science ExploraRead more
(i) Total mass is 75 + 420 + 5 = 500 g. Sugar concentration is 75/500 × 100 = 15 percent, flour is 420/500 × 100 = 84 percent and sodium hydrogencarbonate is 5/500 × 100 = 1 percent. (ii) Copper = 70/100 × 120 = 84 g. Zinc = 120 − 84 = 36 g.
For more NCERT Solutions of Class 9 Science Exploration Chapter 5 Exploring Mixtures and their Separation Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-5/
See lessTwo cars A and B start moving with a constant acceleration from rest, in a straight line. Car A attains a velocity of 5 m s⁻¹ in 5 s. Car B attains a velocity of 3 m s⁻¹ in 10 s. Plot the velocity-time graphs for both the cars in the same graph. Using the graph, calculate the displacement in the two time intervals mentioned (Hint: Calculate the acceleration in both cases). Then calculate their velocities at five instants of time to plot the graph.
For car A, acceleration = (5−0)/5 = 1 m s⁻². Its displacement in 5 s = ½ × 1 × 5² = 12.5 m. For car B, acceleration = (3−0)/10 = 0.3 m s⁻². Its displacement in 10 s = ½ × 0.3 × 10² = 15 m. Thus, both velocity-time graphs are straight lines starting from the origin, with slopes 1 and 0.3 m s⁻², respeRead more
For car A, acceleration = (5−0)/5 = 1 m s⁻². Its displacement in 5 s = ½ × 1 × 5² = 12.5 m. For car B, acceleration = (3−0)/10 = 0.3 m s⁻². Its displacement in 10 s = ½ × 0.3 × 10² = 15 m. Thus, both velocity-time graphs are straight lines starting from the origin, with slopes 1 and 0.3 m s⁻², respectively.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/
See lessOn entering a state highway, a car continues to move with a constant velocity of 6 m s⁻¹ for 2 minutes and then accelerates with a constant acceleration 1 m s⁻² for 6 seconds. Find the displacement of the car on the state highway in the 2 min 6 s time interval by drawing a velocity-time graph for its motion.
For the first 2 minutes = 120 s, the car moves at 6 m s⁻¹. Therefore, displacement = 6 × 120 = 720 m. During the next 6 s, initial velocity is 6 m s⁻¹ and acceleration is 1 m s⁻². Displacement = ut + ½at² = 6 × 6 + ½ × 1 × 36 = 54 m. Hence, total displacement = 720 + 54 = 774 m. For more NCERRead more
For the first 2 minutes = 120 s, the car moves at 6 m s⁻¹. Therefore, displacement = 6 × 120 = 720 m. During the next 6 s, initial velocity is 6 m s⁻¹ and acceleration is 1 m s⁻². Displacement = ut + ½at² = 6 × 6 + ½ × 1 × 36 = 54 m. Hence, total displacement = 720 + 54 = 774 m.
For more NCERT Solutions of Class 9 Science Exploration Chapter 4 Describing Motion Around Us Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-4/
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