1. To find the nth odd number, we use the formula 2n – 1. This means if you want the 5th odd number, it would be 2×5 – 1 = 9. This formula is important because square numbers are formed by the sum of the first n odd numbers. For example, the sum of the first 4 odd numbers (1 + 3 + 5 + 7) equals 16, whiRead more

    To find the nth odd number, we use the formula 2n – 1. This means if you want the 5th odd number, it would be 2×5 – 1 = 9. This formula is important because square numbers are formed by the sum of the first n odd numbers. For example, the sum of the first 4 odd numbers (1 + 3 + 5 + 7) equals 16, which is 4².

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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  2. From 1 to 100, the square numbers are 1² to 10², totaling 10 numbers. From 101 to 200, we have 11² = 121 to 14² = 196, totaling 4 square numbers. As numbers increase, the number of square numbers in each 100-block reduces. The largest perfect square below 1000 is 961, which is 31². This shows how sqRead more

    From 1 to 100, the square numbers are 1² to 10², totaling 10 numbers. From 101 to 200, we have 11² = 121 to 14² = 196, totaling 4 square numbers. As numbers increase, the number of square numbers in each 100-block reduces. The largest perfect square below 1000 is 961, which is 31². This shows how square numbers grow and spread across number ranges.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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  3. There is a pattern where the sum of two consecutive triangular numbers equals a perfect square. Triangular numbers like 1, 3, 6, 10 and 15 when paired successively give squares: 1+3=4, 3+6=9, 6+10=16, 10+15=25. This means the next term would be 15+21 = 36 (6²). This connection reveals how triangularRead more

    There is a pattern where the sum of two consecutive triangular numbers equals a perfect square. Triangular numbers like 1, 3, 6, 10 and 15 when paired successively give squares: 1+3=4, 3+6=9, 6+10=16, 10+15=25. This means the next term would be 15+21 = 36 (6²). This connection reveals how triangular and square numbers are related through addition, showing beautiful patterns in number theory.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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  4. To find the side of a square from its area, we take the square root of the area. Given the area is 49 sq. cm, we find √49 = 7. This is because 7 × 7 = 49. Therefore, the length of each side of the square is 7 cm. This method is used whenever we know the area and want to determine the side length ofRead more

    To find the side of a square from its area, we take the square root of the area. Given the area is 49 sq. cm, we find √49 = 7. This is because 7 × 7 = 49. Therefore, the length of each side of the square is 7 cm. This method is used whenever we know the area and want to determine the side length of a square.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

     

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  5. To find the square root of 64, we ask which number multiplied by itself gives 64. The answer is 8 because 8 × 8 = 64. Also, (–8) × (–8) = 64, but we usually take the positive root. So, √64 = ±8, but in this case, we consider only the positive value. Thus, the square root of 64 is 8.   For moreRead more

    To find the square root of 64, we ask which number multiplied by itself gives 64. The answer is 8 because 8 × 8 = 64. Also, (–8) × (–8) = 64, but we usually take the positive root. So, √64 = ±8, but in this case, we consider only the positive value. Thus, the square root of 64 is 8.

     

    For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/

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