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  1. Asked: In:

    Study the pattern: 1 x 8 + 1 = 9; 12 x 8 + 2 = 98; 123 x 8 + 3 = 987, 1234 x 8 + 4 = 9876; 12345 x 8 + 5 = 98765 Write the next two steps. Can you say how the pattern works?

    Vaishvi

    123456 x 8 + 6 = 987654 1234567 x 8 + 7 = 9876543 Pattern works like this: 1 x 8 + 1 = 9 12 x 8 + 2 = 98 123 x 8 + 3 = 987 1234 x 8 + 4 = 9876 12345 x 8 + 5 = 98765 123456 x 8 + 6 = 987654 1234567 x 8 + 7 = 9875643 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

    123456 x 8 + 6 = 987654
    1234567 x 8 + 7 = 9876543
    Pattern works like this:
    1 x 8 + 1 = 9
    12 x 8 + 2 = 98
    123 x 8 + 3 = 987
    1234 x 8 + 4 = 9876
    12345 x 8 + 5 = 98765
    123456 x 8 + 6 = 987654
    1234567 x 8 + 7 = 9875643

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

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  2. Asked: In:

    Find using distributive property: (a) 728 x 101 (b) 5437 x 1001 (c) 824 x 25 (d) 4275 x 125 (e) 504 x 35

    Best Answer
    Vaishvi

    (a) 728 x 101 = 728 x (100 + 1) = 728 x 100 + 728 x 1 = 72800 + 728 = 73528 (b) 5437 x 1001 = 5437 x (1000 + 1) = 5437 x 1000 + 5437 x 1 = 5437000 + 5437 = 5442437 (c) 824 x 25 = 824 x (20 + 5) = 824 x 20 + 824 x 5 = 16480 + 4120 = 20600 (d) 4275 x 125 = 4275 x (100 + 20 + 5) = 4275 x 100 + 4275 x 2Read more

    (a) 728 x 101
    = 728 x (100 + 1)
    = 728 x 100 + 728 x 1
    = 72800 + 728
    = 73528

    (b) 5437 x 1001
    = 5437 x (1000 + 1)
    = 5437 x 1000 + 5437 x 1
    = 5437000 + 5437
    = 5442437

    (c) 824 x 25
    = 824 x (20 + 5)
    = 824 x 20 + 824 x 5
    = 16480 + 4120
    = 20600

    (d) 4275 x 125
    = 4275 x (100 + 20 + 5)
    = 4275 x 100 + 4275 x 20 + 4275 x5
    = 427500 + 85500 + 21375
    = 534375

    (e) 504 x 35
    = (500 + 4) x 35
    = 500 x 35 + 4 x 35
    = 17500 + 140
    = 17640

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

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  3. Asked: In:

    If the product of two whole number is 1, can we say that one or both of them will be 1? Justify through examples.

    Vaishvi

    If only one number be 1 then the product cannot be 1. Examples: 5 x 1 = 5, 4 x 1 = 4, 8 x 1 = 8 If both number are 1, then the product is 1 1 x 1 = 1 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

    If only one number be 1 then the product cannot be 1.
    Examples: 5 x 1 = 5, 4 x 1 = 4, 8 x 1 = 8
    If both number are 1, then the product is 1
    1 x 1 = 1

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

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  4. Asked: In:

    If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

    Vaishvi

    Yes, if we multiply any number with zero the resultant product will be zero. Example: 2 x 0 = 0, 5 x 0 = 0, 9 x 0 = 0 If both numbers are zero, then the result also be zero. 0 x 0 = 0 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

    Yes, if we multiply any number with zero the resultant product will be zero.
    Example: 2 x 0 = 0, 5 x 0 = 0, 9 x 0 = 0
    If both numbers are zero, then the result also be zero.
    0 x 0 = 0

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

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  6. Asked: In:

    A vendor supplies 32 litres of milk to a hotel in a morning and 68 litres of milk in the evening. If the milk costs ₹15 per litre, how much money is due to the vendor per day?

    Vaishvi

    Supply of milk in morning = 32 litres Supply of milk in evening = 68 litres Total supply = 32 + 68 = 100 litres Now Cost of 1 litre milk = ₹15 Cost of 100 litres milk = 15 x 100 = ₹1500 Therefore, ₹1500 is due to the vendor per day. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapterRead more

    Supply of milk in morning = 32 litres
    Supply of milk in evening = 68 litres
    Total supply = 32 + 68 = 100 litres
    Now
    Cost of 1 litre milk = ₹15
    Cost of 100 litres milk = 15 x 100 = ₹1500
    Therefore, ₹1500 is due to the vendor per day.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/

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