Petrol filled on Monday = 40 litres Petrol filled on next day = 50 litres Total petrol filled = 90 litres Now, Cost of 1 litre petrol = ₹ 44 Cost of 90 litres petrol = 44 x 90 = 44 x (100 – 10) = 44 x 100 – 44 x 10 = 4400 – 440 = ₹ 3960 Therefore, he spent ₹ 3960 on petrol. https://www.tiwariacademyRead more
Petrol filled on Monday = 40 litres
Petrol filled on next day = 50 litres
Total petrol filled = 90 litres
Now,
Cost of 1 litre petrol = ₹ 44
Cost of 90 litres petrol = 44 x 90
= 44 x (100 – 10)
= 44 x 100 – 44 x 10
= 4400 – 440
= ₹ 3960
Therefore, he spent ₹ 3960 on petrol.
(a) 2 x 1768 x 50 = (2 x 50) x 1768 = 100 x 1768 = 176800 (b) 4 x 166 x 25 = (4 x 25) x 166 = 100 x 166 = 16600 (c) 8 x 291 x 125 = (8 x 125) x 291 = 1000 x 291 = 291000 (b) 625 x 279 x 16 = (625 x 16) x 279 = 10000 x 279 = 2790000 (e) 285 x 5 x 60 = 284 x (5 x 60) = 284 x 300 = 85500 (f) 125 x 40 xRead more
(a) 2 x 1768 x 50
= (2 x 50) x 1768
= 100 x 1768
= 176800
(b) 4 x 166 x 25
= (4 x 25) x 166
= 100 x 166
= 16600
(c) 8 x 291 x 125
= (8 x 125) x 291
= 1000 x 291
= 291000
(b) 625 x 279 x 16
= (625 x 16) x 279
= 10000 x 279
= 2790000
(e) 285 x 5 x 60
= 284 x (5 x 60)
= 284 x 300
= 85500
(f) 125 x 40 x 8 x 25
= (125 x 8) x (40 x 25)
= 1000 x 1000
= 1000000
(a) 530 > 503; So 503 appear on left side of 530 on number line. (b) 370 > 307; So 307 appear on left side of 370 on number line. (c) 98765 > 56789; So 56789 appear on left side of 98765 on number line. (d) 9830415 < 10023001; So 9830415 appear on left side of 10023001 on number line. htRead more
(a) 530 > 503;
So 503 appear on left side of 530 on number line.
(b) 370 > 307;
So 307 appear on left side of 370 on number line.
(c) 98765 > 56789;
So 56789 appear on left side of 98765 on number line.
(d) 9830415 < 10023001;
So 9830415 appear on left side of 10023001 on number line.
A taxi-driver, filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ₹ 44 per litre, how much did he spend in all on petrol?
Petrol filled on Monday = 40 litres Petrol filled on next day = 50 litres Total petrol filled = 90 litres Now, Cost of 1 litre petrol = ₹ 44 Cost of 90 litres petrol = 44 x 90 = 44 x (100 – 10) = 44 x 100 – 44 x 10 = 4400 – 440 = ₹ 3960 Therefore, he spent ₹ 3960 on petrol. https://www.tiwariacademyRead more
Petrol filled on Monday = 40 litres
Petrol filled on next day = 50 litres
Total petrol filled = 90 litres
Now,
Cost of 1 litre petrol = ₹ 44
Cost of 90 litres petrol = 44 x 90
= 44 x (100 – 10)
= 44 x 100 – 44 x 10
= 4400 – 440
= ₹ 3960
Therefore, he spent ₹ 3960 on petrol.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/
See lessFind the product using suitable properties: (a) 738 x 103 (b) 854 x 102 (c) 258 x 1008 (d) 1005 x 168
(a) 738 x 103 = 738 x (100 + 3) = 738 x 100 + 738 x 3 = 73800 + 2214 = 76014 (b) 854 x 102 = 854 x (100 + 2) = 854 x 100 + 854 x 2 = 85400 + 1708 = 87108 (c) 258 x 1008 = 258 x (1000 + 8) = 258 x 1000 + 258 x 8 = 258000 + 2064 = 260064 (d) 1005 x 168 = (1000 + 5) x 168 = 1000 x 168 + 5 x 168 = 16800Read more
(a) 738 x 103
= 738 x (100 + 3)
= 738 x 100 + 738 x 3
= 73800 + 2214
= 76014
(b) 854 x 102
= 854 x (100 + 2)
= 854 x 100 + 854 x 2
= 85400 + 1708
= 87108
(c) 258 x 1008
= 258 x (1000 + 8)
= 258 x 1000 + 258 x 8
= 258000 + 2064
= 260064
(d) 1005 x 168
= (1000 + 5) x 168
= 1000 x 168 + 5 x 168
= 168000 + 840
= 168840
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/
See lessFind the product by suitable arrangement: (a) 2 x 1768 x 50 (b) 4 x 166 x 25 (c) 8 x 291 x 125 (d) 625 x 279 x 16 (e) 285 x 5 x 60 (f) 125 x 40 x 8 x 25
(a) 2 x 1768 x 50 = (2 x 50) x 1768 = 100 x 1768 = 176800 (b) 4 x 166 x 25 = (4 x 25) x 166 = 100 x 166 = 16600 (c) 8 x 291 x 125 = (8 x 125) x 291 = 1000 x 291 = 291000 (b) 625 x 279 x 16 = (625 x 16) x 279 = 10000 x 279 = 2790000 (e) 285 x 5 x 60 = 284 x (5 x 60) = 284 x 300 = 85500 (f) 125 x 40 xRead more
(a) 2 x 1768 x 50
= (2 x 50) x 1768
= 100 x 1768
= 176800
(b) 4 x 166 x 25
= (4 x 25) x 166
= 100 x 166
= 16600
(c) 8 x 291 x 125
= (8 x 125) x 291
= 1000 x 291
= 291000
(b) 625 x 279 x 16
= (625 x 16) x 279
= 10000 x 279
= 2790000
(e) 285 x 5 x 60
= 284 x (5 x 60)
= 284 x 300
= 85500
(f) 125 x 40 x 8 x 25
= (125 x 8) x (40 x 25)
= 1000 x 1000
= 1000000
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/
See lessFind the sum by suitable rearrangement: (a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647
(a) 837 + 208 + 363 = (837 + 363) + 208 = 1200 + 208 = 1408 (b) 1962 + 453 + 1538 + 647 = (1962 + 1538) + (453 + 647) = 3500 + 1100 = 4600 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/
(a) 837 + 208 + 363
= (837 + 363) + 208
= 1200 + 208
= 1408
(b) 1962 + 453 + 1538 + 647
= (1962 + 1538) + (453 + 647)
= 3500 + 1100
= 4600
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/
See lessIn each of the following pairs of numbers, state which whole number is on the left of the other number on the number line? Also write them with the appropriate sign (>, <) between them. (a) 530, 503 (b) 370, 307 (c) 98765, 56789 (d) 9830415, 10023001
(a) 530 > 503; So 503 appear on left side of 530 on number line. (b) 370 > 307; So 307 appear on left side of 370 on number line. (c) 98765 > 56789; So 56789 appear on left side of 98765 on number line. (d) 9830415 < 10023001; So 9830415 appear on left side of 10023001 on number line. htRead more
(a) 530 > 503;
So 503 appear on left side of 530 on number line.
(b) 370 > 307;
So 307 appear on left side of 370 on number line.
(c) 98765 > 56789;
So 56789 appear on left side of 98765 on number line.
(d) 9830415 < 10023001;
So 9830415 appear on left side of 10023001 on number line.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-2/
See less