Cloth bought for shirt = 3 m 20 cm = 3.20 m Cloth bought for trouser = 2 m 5 cm = 2.05 m Total length of cloth bought by Nasreen = 3.20 + 2.05 = 5.25 m Therefore, the total length of cloth bought by Nasreen is 5.25 m https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Cloth bought for shirt = 3 m 20 cm = 3.20 m
Cloth bought for trouser = 2 m 5 cm = 2.05 m
Total length of cloth bought by Nasreen = 3.20 + 2.05 = 5.25 m
Therefore, the total length of cloth bought by Nasreen is 5.25 m
Money given by mother = ₹10.50 Money given by father = ₹15.80 Total money received by Radhika = ₹10.50 + ₹15.80 = ₹26.30 Therefore, the total money received by Radhika is ₹26.30. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Money given by mother = ₹10.50
Money given by father = ₹15.80
Total money received by Radhika = ₹10.50 + ₹15.80 = ₹26.30
Therefore, the total money received by Radhika is ₹26.30.
Money spent for Maths book = ₹35.75 Money spent for Science book = ₹32.60 Total money spent = ₹35.75 + ₹32.60 = ₹68.35 Therefore, total money spent by Rashid is ₹68.35. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Money spent for Maths book = ₹35.75
Money spent for Science book = ₹32.60
Total money spent = ₹35.75 + ₹32.60 = ₹68.35
Therefore, total money spent by Rashid is ₹68.35.
Before comparing, we write both terms in like decimals: (a) 0.3 0.02 (c) 3.0 or 0.8 ⇒ 3.0 > 0.8 (d) 0.50 or 0.05 ⇒ 0.50 > 0.05 (e) 1.23 or 1.20 ⇒ 1.23 > 1.20 (f) 0.099 or 0.190 ⇒ 0.099 < 0.190 (g) 1.50 or 1.50 ⇒ 1.50 = 1.50 (h) 1.431 5.603 (k) Five more examples: 1) 1.8 or 1.82 2) 1.0009Read more
Before comparing, we write both terms in like decimals:
(a) 0.3 0.02
(c) 3.0 or 0.8 ⇒ 3.0 > 0.8
(d) 0.50 or 0.05 ⇒ 0.50 > 0.05
(e) 1.23 or 1.20 ⇒ 1.23 > 1.20
(f) 0.099 or 0.190 ⇒ 0.099 < 0.190
(g) 1.50 or 1.50 ⇒ 1.50 = 1.50
(h) 1.431 5.603
(k) Five more examples:
1) 1.8 or 1.82
2) 1.0009 or 1.09
3) 10.01 or 100.1
4) 5.100 or 5.0100
5) 04.213 or 0421.3
Before comparing, we write both terms in like decimals
1) 1.80 or 1.82 ⇒ 1.82 is greater than 1.8
2) 1.0009 or 1.0900 ⇒ 1.09 is greater than 1.0009
3) 10.01 or 100.10 ⇒ 100.1 is greater than 10.01
4) 5.1000 or 5.0100 ⇒ 5.100 is greater than 5.0100
5) 04.213 or 0421.300 ⇒ 0421.3 is greater than 04.213
Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.
Cloth bought for shirt = 3 m 20 cm = 3.20 m Cloth bought for trouser = 2 m 5 cm = 2.05 m Total length of cloth bought by Nasreen = 3.20 + 2.05 = 5.25 m Therefore, the total length of cloth bought by Nasreen is 5.25 m https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Cloth bought for shirt = 3 m 20 cm = 3.20 m
Cloth bought for trouser = 2 m 5 cm = 2.05 m
Total length of cloth bought by Nasreen = 3.20 + 2.05 = 5.25 m
Therefore, the total length of cloth bought by Nasreen is 5.25 m
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessRadhika’s mother have her ₹10.50 and her father gave her ₹15.80. Find the total amount given to Radhika by the parents.
Money given by mother = ₹10.50 Money given by father = ₹15.80 Total money received by Radhika = ₹10.50 + ₹15.80 = ₹26.30 Therefore, the total money received by Radhika is ₹26.30. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Money given by mother = ₹10.50
Money given by father = ₹15.80
Total money received by Radhika = ₹10.50 + ₹15.80 = ₹26.30
Therefore, the total money received by Radhika is ₹26.30.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessRashid spent ₹35.75 for Maths book and ₹32.60 for Science book. Find the total amount spent by Rashid.
Money spent for Maths book = ₹35.75 Money spent for Science book = ₹32.60 Total money spent = ₹35.75 + ₹32.60 = ₹68.35 Therefore, total money spent by Rashid is ₹68.35. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
Money spent for Maths book = ₹35.75
Money spent for Science book = ₹32.60
Total money spent = ₹35.75 + ₹32.60 = ₹68.35
Therefore, total money spent by Rashid is ₹68.35.
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessExpress as kg using decimals: 2 g
∴ 1 g = 1/1000 kg ∴ 2 g = 1/1000 x 2 = 0.002 kg https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
∴ 1 g = 1/1000 kg
∴ 2 g = 1/1000 x 2 = 0.002 kg
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessExpress as km using decimals: 8 m
∴ 1 m = 1/1000 km ∴ 8 m = 1/1000 x 8 = 0.008 km https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
∴ 1 m = 1/1000 km
∴ 8 m = 1/1000 x 8 = 0.008 km
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessExpress as cm using decimals: (a) 5 mm
∴ 1 mm = 1/10 cm ∴ 5 mm = 1/10x 5 = 0.5 cm https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
∴ 1 mm = 1/10 cm
∴ 5 mm = 1/10x 5 = 0.5 cm
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessExpress as meters using decimals: 15 cm
∴1 cm = 1/100 m ∴15 cm = 1/100x 15 = 0.15 m https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
∴1 cm = 1/100 m
∴15 cm = 1/100x 15 = 0.15 m
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessExpress as rupees using decimals: 5 paise
∴1 paisa = ₹ 1/100 ∴5 paise = 1/100x5 = ₹ 0.05 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
∴1 paisa = ₹ 1/100
∴5 paise = 1/100×5 = ₹ 0.05
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessWhich is greater: (a) 0.3 or 0.4 (b) 0.07 or 0.02 (c) 3 or 0.8 (d) 0.5 or 0.05 (e) 1.23 or 1.2 (f) 0.099 or 0.19 (g) 1.5 or 1.50 (h) 1.431 or 1.490 (i) 3.3 or 3.300 (j) 5.64 or 5.603 (k) Make five more examples and find the greater.
Before comparing, we write both terms in like decimals: (a) 0.3 0.02 (c) 3.0 or 0.8 ⇒ 3.0 > 0.8 (d) 0.50 or 0.05 ⇒ 0.50 > 0.05 (e) 1.23 or 1.20 ⇒ 1.23 > 1.20 (f) 0.099 or 0.190 ⇒ 0.099 < 0.190 (g) 1.50 or 1.50 ⇒ 1.50 = 1.50 (h) 1.431 5.603 (k) Five more examples: 1) 1.8 or 1.82 2) 1.0009Read more
Before comparing, we write both terms in like decimals:
(a) 0.3 0.02
(c) 3.0 or 0.8 ⇒ 3.0 > 0.8
(d) 0.50 or 0.05 ⇒ 0.50 > 0.05
(e) 1.23 or 1.20 ⇒ 1.23 > 1.20
(f) 0.099 or 0.190 ⇒ 0.099 < 0.190
(g) 1.50 or 1.50 ⇒ 1.50 = 1.50
(h) 1.431 5.603
(k) Five more examples:
1) 1.8 or 1.82
2) 1.0009 or 1.09
3) 10.01 or 100.1
4) 5.100 or 5.0100
5) 04.213 or 0421.3
Before comparing, we write both terms in like decimals
1) 1.80 or 1.82 ⇒ 1.82 is greater than 1.8
2) 1.0009 or 1.0900 ⇒ 1.09 is greater than 1.0009
3) 10.01 or 100.10 ⇒ 100.1 is greater than 10.01
4) 5.1000 or 5.0100 ⇒ 5.100 is greater than 5.0100
5) 04.213 or 0421.300 ⇒ 0421.3 is greater than 04.213
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See lessWrite as fractions in lowest terms: (a) 0.60 (b) 0.05 (c) 0.75 (d) 0.18 (e) 0.25 (f) 0.125 (g) 0.066
(a) 0.60 = 3/5 (b) 0.05 = 1/20 (c) 0.75 = 3/4 (d) 0.18 = 9/50 (e) 0.25 = 1/4 (f) 0.125 = 1/8 (g) 0.066 = 33/500 https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
(a) 0.60 = 3/5
(b) 0.05 = 1/20
(c) 0.75 = 3/4
(d) 0.18 = 9/50
(e) 0.25 = 1/4
(f) 0.125 = 1/8
(g) 0.066 = 33/500
https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/
See less