1. Weight of onions = 3 kg 500 g = 3.500 kg Weight of tomatoes = 2 kg 75 g = 2.075 kg Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg Thus, the weight of potatoes is 4.425 kg. https://www.tiwariacademy.com/ncert-solutions/class-6/Read more

    Weight of onions = 3 kg 500 g = 3.500 kg
    Weight of tomatoes = 2 kg 75 g = 2.075 kg
    Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg
    Therefore, weight of potatoes = 10.000 – 5.575 = 4.425 kg
    Thus, the weight of potatoes is 4.425 kg.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

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  2. Total distance travel = 20 km 50 m = 20.050 km Distance travelled by bus = 10 km 200 m = 10.200 km Distance travelled by auto = 20.050 – 10.200 = 9.850 km Therefore, 9.850 km distance travels by auto. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

    Total distance travel = 20 km 50 m = 20.050 km
    Distance travelled by bus = 10 km 200 m = 10.200 km
    Distance travelled by auto = 20.050 – 10.200 = 9.850 km
    Therefore, 9.850 km distance travels by auto.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

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    • 6
  3. Total length of cloth = 20 m 5 cm = 20.05 m Length of cloth used = 4 m 50 cm = 4.50 m Remaining cloth = 20.05 m – 4.50 m = 15.55 m Therefore, 15.55 m of cloth is left with Tina. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

    Total length of cloth = 20 m 5 cm = 20.05 m
    Length of cloth used = 4 m 50 cm = 4.50 m
    Remaining cloth = 20.05 m – 4.50 m = 15.55 m
    Therefore, 15.55 m of cloth is left with Tina.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

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    • 4
  4. Total money = ₹18.50 Cost of Ice-cream = ₹11.75 Amount left = ₹18.50 – ₹11.75 = ₹6.75 Therefore, Rani has ₹6.75 now. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

    Total money = ₹18.50
    Cost of Ice-cream = ₹11.75
    Amount left = ₹18.50 – ₹11.75
    = ₹6.75
    Therefore, Rani has ₹6.75 now.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

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  5. Total amount given to shopkeeper = ₹50 Cost of book = ₹35.65 Amount left = ₹50.00 – ₹35.65 = ₹14.35 Therefore, Raju got back ₹14.35 from the shopkeeper. https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

    Total amount given to shopkeeper = ₹50
    Cost of book = ₹35.65
    Amount left = ₹50.00 – ₹35.65
    = ₹14.35
    Therefore, Raju got back ₹14.35 from the shopkeeper.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-8/

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    • 3