When a ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet, it will move away from the magnet. This happens because a superconductor exhibits ideal diamagnetic behavior (Meissner effect), repelling magnetic field lines. For more visit here: https://www.tiwariacRead more
When a ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet, it will move away from the magnet. This happens because a superconductor exhibits ideal diamagnetic behavior (Meissner effect), repelling magnetic field lines.
The capacitance of the capacitor can be calculated using the formula C = 1/Xc2πv Given Xc =100Ω and v = 5000/π Hz, C =1/1002π 5000/π = 10-⁶ F = 1μF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The capacitance of the capacitor can be calculated using the formula C = 1/Xc2πv
Given Xc =100Ω and v = 5000/π Hz, C =1/1002π 5000/π = 10-⁶ F = 1μF.
When an iron core is inserted into a solenoid connected to a battery, the current decreases. The iron core increases the magnetic field and flux within the solenoid. According to Lenz's law, the induced current opposes this change in magnetic flux, resisting the increase. Consequently, an induced cuRead more
When an iron core is inserted into a solenoid connected to a battery, the current decreases. The iron core increases the magnetic field and flux within the solenoid. According to Lenz’s law, the induced current opposes this change in magnetic flux, resisting the increase. Consequently, an induced current is set up opposite to the battery current, reducing the overall current flow in the solenoid.
For an AC current I = Im sin(ωt), the equivalent DC current that produces the same heat H in a resistor R over time T= 2π/ω is I effective = Im/√2. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
For an AC current I = Im sin(ωt), the equivalent DC current that produces the same heat H in a resistor R over time T= 2π/ω is I effective = Im/√2.
The electric mains in a house marked 220 V and 50 Hz have an instantaneous voltage equation given by V =220√2 sin (2π(50)t) = 311sin(314t). Here, 311 V is the peak voltage, and 50 Hz is the frequency. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The electric mains in a house marked 220 V and 50 Hz have an instantaneous voltage equation given by V =220√2 sin (2π(50)t) = 311sin(314t). Here, 311 V is the peak voltage, and 50 Hz is the frequency.
In a series LCR circuit, the voltages across the inductor (Vl = 20V) and capacitor (V c = 20V) cancel each other, making the circuit effectively resistive. Therefore, the phase difference between the applied voltage and the current is zero. For more visit here: https://www.tiwariacademy.com/ncert-soRead more
In a series LCR circuit, the voltages across the inductor (Vl = 20V) and capacitor (V c = 20V) cancel each other, making the circuit effectively resistive. Therefore, the phase difference between the applied voltage and the current is zero.
The material is diamagnetic because its relative permeability (μ r = 0.5) is less than 1. For a diamagnetic material, the magnetic susceptibility (χ) is related to relative permeability by χ = μr −1. Here, χ = −0.5. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/Read more
The material is diamagnetic because its relative permeability (μ r = 0.5) is less than 1. For a diamagnetic material, the magnetic susceptibility (χ) is related to relative permeability by χ = μr −1. Here, χ = −0.5.
The average power supplied by an AC source to a capacitor over a complete cycle is zero. This is because the current and voltage in a capacitor differ in phase by π/2, resulting in no net energy transfer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The average power supplied by an AC source to a capacitor over a complete cycle is zero. This is because the current and voltage in a capacitor differ in phase by
π/2, resulting in no net energy transfer.
Capacitive reactance is the opposition offered by a capacitor to the flow of alternating current. It is given by the formula X c = 1/Cω, where C is the capacitance and ω is the angular frequency. Its SI unit is ohm (Ω). For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physRead more
Capacitive reactance is the opposition offered by a capacitor to the flow of alternating current. It is given by the formula X c = 1/Cω, where C is the capacitance and ω is the angular frequency. Its SI unit is ohm (Ω).
For an ideal inductor connected across a sinusoidal A.C. voltage source, the average power over the full cycle is zero. This is because the voltage and current are out of phase by π/2, resulting in no net energy transfer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/phRead more
For an ideal inductor connected across a sinusoidal A.C. voltage source, the average power over the full cycle is zero. This is because the voltage and current are out of phase by π/2, resulting in no net energy transfer.
A ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet. in which direction will it move and why?
When a ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet, it will move away from the magnet. This happens because a superconductor exhibits ideal diamagnetic behavior (Meissner effect), repelling magnetic field lines. For more visit here: https://www.tiwariacRead more
When a ball of superconducting material is dipped in liquid nitrogen and placed near a bar magnet, it will move away from the magnet. This happens because a superconductor exhibits ideal diamagnetic behavior (Meissner effect), repelling magnetic field lines.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-5/
Find the capacitance of the capacitor that would have a reactance of 100Ω when used with an a.c. source of frequency 5/π kHz.
The capacitance of the capacitor can be calculated using the formula C = 1/Xc2πv Given Xc =100Ω and v = 5000/π Hz, C =1/1002π 5000/π = 10-⁶ F = 1μF. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The capacitance of the capacitor can be calculated using the formula C = 1/Xc2πv
Given Xc =100Ω and v = 5000/π Hz, C =1/1002π 5000/π = 10-⁶ F = 1μF.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
A solenoid is connected to a battery so that a steady current flows through it. if an iron core is inserted into the solenoid, will the current increase or decrease?
When an iron core is inserted into a solenoid connected to a battery, the current decreases. The iron core increases the magnetic field and flux within the solenoid. According to Lenz's law, the induced current opposes this change in magnetic flux, resisting the increase. Consequently, an induced cuRead more
When an iron core is inserted into a solenoid connected to a battery, the current decreases. The iron core increases the magnetic field and flux within the solenoid. According to Lenz’s law, the induced current opposes this change in magnetic flux, resisting the increase. Consequently, an induced current is set up opposite to the battery current, reducing the overall current flow in the solenoid.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-6/
An a.c. I = Im sin wt produces certain heat H in a resistor R over a time T = 2π/w . write the value of d.c. that would produce the same heat in the same resistor in the same time.
For an AC current I = Im sin(ωt), the equivalent DC current that produces the same heat H in a resistor R over time T= 2π/ω is I effective = Im/√2. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
For an AC current I = Im sin(ωt), the equivalent DC current that produces the same heat H in a resistor R over time T= 2π/ω is I effective = Im/√2.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The electric mains in the house are marked 220 V, 50Hz. Write down the equuation for instantaneous voltage.
The electric mains in a house marked 220 V and 50 Hz have an instantaneous voltage equation given by V =220√2 sin (2π(50)t) = 311sin(314t). Here, 311 V is the peak voltage, and 50 Hz is the frequency. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The electric mains in a house marked 220 V and 50 Hz have an instantaneous voltage equation given by V =220√2 sin (2π(50)t) = 311sin(314t). Here, 311 V is the peak voltage, and 50 Hz is the frequency.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
In a series LCR circuit, the voltage across an inductor, a capacitor and a resistor are 20 V, 20 V and 40 V, respectively, What is the phase difference between the applied voltage and the current in the circuit?
In a series LCR circuit, the voltages across the inductor (Vl = 20V) and capacitor (V c = 20V) cancel each other, making the circuit effectively resistive. Therefore, the phase difference between the applied voltage and the current is zero. For more visit here: https://www.tiwariacademy.com/ncert-soRead more
In a series LCR circuit, the voltages across the inductor (Vl = 20V) and capacitor (V c = 20V) cancel each other, making the circuit effectively resistive. Therefore, the phase difference between the applied voltage and the current is zero.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
Relative permeability of a material .u^r = 0.5. Identify the nature of the magnetic material and wright its relation to magnetic susceptibility.
The material is diamagnetic because its relative permeability (μ r = 0.5) is less than 1. For a diamagnetic material, the magnetic susceptibility (χ) is related to relative permeability by χ = μr −1. Here, χ = −0.5. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/Read more
The material is diamagnetic because its relative permeability (μ r = 0.5) is less than 1. For a diamagnetic material, the magnetic susceptibility (χ) is related to relative permeability by χ = μr −1. Here, χ = −0.5.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
How much average power, over a complete cycle, does an a.c.source supply to a capacitor?
The average power supplied by an AC source to a capacitor over a complete cycle is zero. This is because the current and voltage in a capacitor differ in phase by π/2, resulting in no net energy transfer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
The average power supplied by an AC source to a capacitor over a complete cycle is zero. This is because the current and voltage in a capacitor differ in phase by
π/2, resulting in no net energy transfer.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
Difine capacitive reactance. write its SI units.
Capacitive reactance is the opposition offered by a capacitor to the flow of alternating current. It is given by the formula X c = 1/Cω, where C is the capacitance and ω is the angular frequency. Its SI unit is ohm (Ω). For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physRead more
Capacitive reactance is the opposition offered by a capacitor to the flow of alternating current. It is given by the formula X c = 1/Cω, where C is the capacitance and ω is the angular frequency. Its SI unit is ohm (Ω).
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
For an ideal Inductor, connected across a sinusoidal a.c. voltage source, state which one of the following quantity is zero: (i) instantaneous power, (ii) average power over full cycle of the a.c. voltage source.
For an ideal inductor connected across a sinusoidal A.C. voltage source, the average power over the full cycle is zero. This is because the voltage and current are out of phase by π/2, resulting in no net energy transfer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/phRead more
For an ideal inductor connected across a sinusoidal A.C. voltage source, the average power over the full cycle is zero. This is because the voltage and current are out of phase by π/2, resulting in no net energy transfer.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/