(i) The reactive element causing the current to lag the voltage by a phase angle of π/2 is an inductor. (ii) The reactive element causing the current to lead the voltage by π/2 is a capacitor. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
(i) The reactive element causing the current to lag the voltage by a phase angle of π/2 is an inductor.
(ii) The reactive element causing the current to lead the voltage by π/2 is a capacitor.
Since the current and voltage are in phase, the power factor cosϕ = 1. The power dissipation is given by P = V rms I rms For Vrms = 200V and I rms = 10 A, the power dissipation is P = 1/2 × 200 × 10 = 1000 W. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapterRead more
Since the current and voltage are in phase, the power factor cosϕ = 1. The power dissipation is given by P = V rms I rms
For Vrms = 200V and I rms = 10 A,
the power dissipation is P = 1/2 × 200 × 10 = 1000 W.
Wattless current is the current that does not dissipate power in a circuit, even though current flows. It occurs in purely inductive or capacitive circuits where the power factor is zero, and no net energy is transferred. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/phRead more
Wattless current is the current that does not dissipate power in a circuit, even though current flows. It occurs in purely inductive or capacitive circuits where the power factor is zero, and no net energy is transferred.
Mutual inductance between two coils is the amount of magnetic flux linked with one coil when a unit current flows through the other coil. It quantifies the coupling effect between the coils due to magnetic interaction. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physiRead more
Mutual inductance between two coils is the amount of magnetic flux linked with one coil when a unit current flows through the other coil. It quantifies the coupling effect between the coils due to magnetic interaction.
When a bulb and capacitor are connected in series to an A.C. source, increasing the frequency reduces the capacitive reactance X c, which decreases the circuit's impedance. As a result, current increases, making the bulb's brightness increase with frequency. For more visit here: https://www.tiwariacRead more
When a bulb and capacitor are connected in series to an A.C. source, increasing the frequency reduces the capacitive reactance X c, which decreases the circuit’s impedance. As a result, current increases, making the bulb’s brightness increase with frequency.
A reactive element, in an a.c. circuit, causes the current flowing (i) to lag in phase by π/2 , (ii) to lead in phase by π/2 with respect to the applied voltage. Identify the element in each case.
(i) The reactive element causing the current to lag the voltage by a phase angle of π/2 is an inductor. (ii) The reactive element causing the current to lead the voltage by π/2 is a capacitor. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
(i) The reactive element causing the current to lag the voltage by a phase angle of π/2 is an inductor.
(ii) The reactive element causing the current to lead the voltage by π/2 is a capacitor.
For more visit here:
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The instantaneous current and voltage of an a.c. circuit are given by I = 10 sin 300t A and V = 200 sin 300t V. What is the Power dissipation in the curcuit?
Since the current and voltage are in phase, the power factor cosϕ = 1. The power dissipation is given by P = V rms I rms For Vrms = 200V and I rms = 10 A, the power dissipation is P = 1/2 × 200 × 10 = 1000 W. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapterRead more
Since the current and voltage are in phase, the power factor cosϕ = 1. The power dissipation is given by P = V rms I rms
For Vrms = 200V and I rms = 10 A,
the power dissipation is P = 1/2 × 200 × 10 = 1000 W.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
What is wattless current?
Wattless current is the current that does not dissipate power in a circuit, even though current flows. It occurs in purely inductive or capacitive circuits where the power factor is zero, and no net energy is transferred. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/phRead more
Wattless current is the current that does not dissipate power in a circuit, even though current flows. It occurs in purely inductive or capacitive circuits where the power factor is zero, and no net energy is transferred.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
Difine the term ‘mutual inductance’ between the two coils.
Mutual inductance between two coils is the amount of magnetic flux linked with one coil when a unit current flows through the other coil. It quantifies the coupling effect between the coils due to magnetic interaction. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physiRead more
Mutual inductance between two coils is the amount of magnetic flux linked with one coil when a unit current flows through the other coil. It quantifies the coupling effect between the coils due to magnetic interaction.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/
A bulb and a capacitor are connectedin series to an a.c. source of variable frequency. How will the brightness of the bulb change on increasing the frequency of the a.c. source. Give reason.
When a bulb and capacitor are connected in series to an A.C. source, increasing the frequency reduces the capacitive reactance X c, which decreases the circuit's impedance. As a result, current increases, making the bulb's brightness increase with frequency. For more visit here: https://www.tiwariacRead more
When a bulb and capacitor are connected in series to an A.C. source, increasing the frequency reduces the capacitive reactance X c, which decreases the circuit’s impedance. As a result, current increases, making the bulb’s brightness increase with frequency.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/