(i) Highest resistance can be obtained by connecting the four coils in series. Then, R = 4Ω + 8Ω + 12Ω + 24Ω = 48Ω (ii) Lowest resistance can be obtained by connecting the four coils in parallel. 1/r = 1/4 +1/8+1/12+1/24=12/24=1/2 R= 2ohm.
(i) Highest resistance can be obtained by connecting the four coils in series.
Then, R = 4Ω + 8Ω + 12Ω + 24Ω = 48Ω
(ii) Lowest resistance can be obtained by connecting the four coils in parallel.
(i) We can get a total resistance of 4Ω by connecting the 2Ω resistance in series with the parallel combination of 3Ω and 6Ω. R= R1 + (R2 x R3)/ (R2 + R3) = 2 + (3 x 6)/ (3+6) = 4 ohm. (ii) We can obtain a total resistance of 1Ω by connecting resistors of 2 Ω, 3 Ω and 6 Ω in parallel. 1/R = 1/R1 + 1Read more
(i) We can get a total resistance of 4Ω by connecting the 2Ω resistance in series with the parallel combination of 3Ω and 6Ω.
R= R1 + (R2 x R3)/ (R2 + R3)
= 2 + (3 x 6)/ (3+6) = 4 ohm.
(ii) We can obtain a total resistance of 1Ω by connecting resistors of 2 Ω, 3 Ω and 6 Ω in parallel.
Advantages of connecting electrical devices in parallel with the battery are : In parallel circuits, if an electrical appliance stops working due to some defect, then all other appliances keep working normally. In parallel circuits, each electrical appliance has its own switch due to which it can beRead more
Advantages of connecting electrical devices in parallel with the battery are :
In parallel circuits, if an electrical appliance stops working due to some defect, then all other appliances keep working normally.
In parallel circuits, each electrical appliance has its own switch due to which it can be turned on turned off independently, without affecting other appliances.
In parallel circuits, each electrical appliance gets the same voltage (220 V) as that of the power supply line.
In the parallel connection of electrical appliances, the overall resistance of the household circuit is reduced due to which the current from the power supply is high.
Resistance of electric lamp, R1 = 100 Ω Resistance of toaster, R2 = 50 Ω Resistance of water filter, R3 = 500 Ω Equivalent resistance Rp of the three appliances connected in parallel, is 1/100+1/50+1/500 =5+10+1/500 = 16/500 ⟹ 𝑅 = 500/16 =31.25 Ω Resistance of electric iron = Equivalent resistance oRead more
Resistance of electric lamp, R1 = 100 Ω
Resistance of toaster, R2 = 50 Ω
Resistance of water filter, R3 = 500 Ω
Equivalent resistance Rp of the three appliances connected in parallel, is
When the resistances are connected in parallel, the equivalent resistance is smaller than the smallest individual resistance. (i) Equivalent resistance < 1 Ω. (ii) Equivalent resistance < 1 Ω.
When the resistances are connected in parallel, the equivalent resistance is smaller than the smallest individual resistance.
(i) Equivalent resistance < 1 Ω.
(ii) Equivalent resistance < 1 Ω.
What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 ohm, 8 ohm, 12 ohm, 24 ohm?
(i) Highest resistance can be obtained by connecting the four coils in series. Then, R = 4Ω + 8Ω + 12Ω + 24Ω = 48Ω (ii) Lowest resistance can be obtained by connecting the four coils in parallel. 1/r = 1/4 +1/8+1/12+1/24=12/24=1/2 R= 2ohm.
(i) Highest resistance can be obtained by connecting the four coils in series.
Then, R = 4Ω + 8Ω + 12Ω + 24Ω = 48Ω
(ii) Lowest resistance can be obtained by connecting the four coils in parallel.
1/r = 1/4 +1/8+1/12+1/24=12/24=1/2
R= 2ohm.
See lessHow can three resistors of resistances 2 ohm, 3 ohm, and 6 ohm be connected to give a total resistance of (a) 4 ohm, (b) 1 ohm?
(i) We can get a total resistance of 4Ω by connecting the 2Ω resistance in series with the parallel combination of 3Ω and 6Ω. R= R1 + (R2 x R3)/ (R2 + R3) = 2 + (3 x 6)/ (3+6) = 4 ohm. (ii) We can obtain a total resistance of 1Ω by connecting resistors of 2 Ω, 3 Ω and 6 Ω in parallel. 1/R = 1/R1 + 1Read more
(i) We can get a total resistance of 4Ω by connecting the 2Ω resistance in series with the parallel combination of 3Ω and 6Ω.
R= R1 + (R2 x R3)/ (R2 + R3)
= 2 + (3 x 6)/ (3+6) = 4 ohm.
(ii) We can obtain a total resistance of 1Ω by connecting resistors of 2 Ω, 3 Ω and 6 Ω in parallel.
1/R = 1/R1 + 1/R2 = 1/2 +1/3+ 1/6 =1 ohm.
See lessWhat are the advantages of connecting electrical devices in parallel with the battery instead of connecting them in series?
Advantages of connecting electrical devices in parallel with the battery are : In parallel circuits, if an electrical appliance stops working due to some defect, then all other appliances keep working normally. In parallel circuits, each electrical appliance has its own switch due to which it can beRead more
Advantages of connecting electrical devices in parallel with the battery are :
- In parallel circuits, if an electrical appliance stops working due to some defect, then all other appliances keep working normally.
- In parallel circuits, each electrical appliance has its own switch due to which it can be turned on turned off independently, without affecting other appliances.
- In parallel circuits, each electrical appliance gets the same voltage (220 V) as that of the power supply line.
- In the parallel connection of electrical appliances, the overall resistance of the household circuit is reduced due to which the current from the power supply is high.
See lessAn electric lamp of 100 ohm, a toaster of resistance 50 ohm, and a water filter of resistance 500 ohm are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?
Resistance of electric lamp, R1 = 100 Ω Resistance of toaster, R2 = 50 Ω Resistance of water filter, R3 = 500 Ω Equivalent resistance Rp of the three appliances connected in parallel, is 1/100+1/50+1/500 =5+10+1/500 = 16/500 ⟹ 𝑅 = 500/16 =31.25 Ω Resistance of electric iron = Equivalent resistance oRead more
Resistance of electric lamp, R1 = 100 Ω
Resistance of toaster, R2 = 50 Ω
Resistance of water filter, R3 = 500 Ω
Equivalent resistance Rp of the three appliances connected in parallel, is
1/100+1/50+1/500 =5+10+1/500 = 16/500 ⟹ 𝑅 = 500/16 =31.25 Ω
Resistance of electric iron = Equivalent resistance of the three appliances connected in parallel = 31.25 Ω
Applied voltage, V = 220 V
𝐼=𝑉/𝑅 = 220 𝑉/31.25 Ω = 7.04 𝐴
See lessJudge the equivalent resistance when the following are connected in parallel
When the resistances are connected in parallel, the equivalent resistance is smaller than the smallest individual resistance. (i) Equivalent resistance < 1 Ω. (ii) Equivalent resistance < 1 Ω.
When the resistances are connected in parallel, the equivalent resistance is smaller than the smallest individual resistance.
See less(i) Equivalent resistance < 1 Ω.
(ii) Equivalent resistance < 1 Ω.